我有一套办法接收一个阵列,然后在NSO物体中储存。
- (void)updatePoints:(NSArray *)pointArrayPassed
{
pointArray = pointArrayPassed;
pointCount= pointArray.count;
}
下面的法典是行之有效的,但显然保留了ArrayPassed的点子,这样,我就可以把这个点 reflects倒。 然而,如果我使用ArrayPassed号的复印件,那就开始大量泄漏!
职能中是否有办法只通过这样的价值观而不是点子?
你可以不释放目前的物体,而只是把复制件贴在单瓦拉。 否则,你就失去了可以发送<代码>release电文的发号人,这就是为什么电文遍布各地。
这是更好的替代。
- (void)updatePoints:(NSArray *)pointArrayPassed
{
if (pointArray == pointArrayPassed) {
//the new array is the same as the current one. Do nothing
return;
}
[pointArray release];
pointArray = [pointArrayPassed copy];
pointCount = pointArray.count;
}
But it s not the most elegant way of doing it.
更好的办法是将Array作为财产申报如下:copy,作为其记忆管理周期(很明显,因为你有一个可变/可变的分类组)。 还有一种称为<代码>-pointCount的单独方法,必要时可重新计算。
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