Question

• 我如何将新添入的<代码>的项目合并起来。清单。

我有一个<代码>adapter,在我名单上增列新项目时,我说:adapter.notificationDataSetChanged();增列了这些物品,但一切都是完美的,但我想是新增加的内容来作一些估计。

Answer 1

<代码>Animate 每添加以下内容:getView(, 您的Custompter。

public View getView(int position, View convertView, ViewGroup parent) {

    View v = convertView;

    if (v == null) {
        LayoutInflater vi = (LayoutInflater) getActivity()
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        v = vi.inflate(R.layout.simple_list_item_1, null);
    }

    ListData o = list.get(position);
    TextView tt = (TextView) v.findViewById(R.id.toptext);

    tt.setText(o.content);

    Log.d("ListTest", "Position : "+position);
    if(flag == false) {
        Animation animation = AnimationUtils
                .loadAnimation(getActivity(), R.anim.slide_top_to_bottom);
        v.startAnimation(animation);
    }
    return v;
}

从而达到<代码>Animation。

Answer 2

官方关于安乐文的docs言说,在布局发生变化时,你可以采用“android:animateLayoutChanges=“true”,为触发。

http://developer.android.com/training/animation/layout.html。

Answer 3

增加这种估计比我最初想象的要困难。这两种方式取决于你想要达到的那种估计。

Using LayoutAnimationController. There is an example in the API demos.
每一条<条码>:

这确实是一个黑体,但我发现的唯一途径是给<代码>添加一im。子女:

You can try notifying the adapter the id of the item you are willing to delete and call adapter.notifyDataSetChanged();. This will generate calls to the adapter s getView() method. Inside it you can do something like:

if ( item.getId() == itemToRemove ) {
 //apply the animation
}

After the animation finished you can recall adapter.notifyDataSetChanged() to put everything in place.

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