Question

I have a person array, with a key n for name. The value for n is an array, with key l (short for last ) having the value I want to get at, the last name.

出于奇怪的方案拟订原因,我用最后名称“地址”作为string。

How do I do this?
I ve tried eval, among others.

共和国我是清楚的!

我想要的是利用变数的测试获得。

例如:

$person[$test]

(显然没有工作,但又做了些什么?)

。例如,有时会有<条码>[][居民][街道]。

<?php

    $test = "[ n ][ l ]";

    echo "I ve got a string with the array index ".$test. "
";

    $person = array("n"=>array( l => SMITH ));

    echo  the array, $person, is this:  ."
";
    print_r($person);

    echo "What I want is ".$person[ n ][ l ]. "
";
    ?>

Output:

I ve got a string with the array index [ n ][ l ]
the array, $person, is this: 

    Array
    (
        [n] => Array
            (
                [l] => SMITH
            )

    )

我想的是SMITH。

Answer 1

相对而言,只有两种选择:

使用 rel=“nofollow”> 。

function IAmEvilSoYouShouldNotCallMe($array, $key) {
    return eval( return $array  . $key .  ; );
}

echo IAmEvilSoYouShouldNotCallMe(
    array("n"=>array( l => SMITH )),
    "[ n ][ l ]"
);

Or:

function helper($array, $key) {
    $keys = array_map(function ($val) {
        return trim($val, "][ ");
    }, explode( ][ , $key));    

    while ($key = array_shift($keys)) {
        if (isset($array[$key])) {
            $array = $array[$key];
            continue;
        }

        return null;
    }

    return $array;
}

echo helper(
    array("n"=>array( l => SMITH )),
    "[ n ][ l ]"
);

两项产出:

SMITH

Answer 2

我认为,这将使这项工作成为你期望它:

http://codepad.org/M3jRDg99“rel=“nofollow”http://codepad.org/M3jRDg99 。

eval("echo $person$test;");

我假定,这可能是因为你不得不从事 dollar美元标记的工作。

Answer 3

我看不出有任何合理理由在此案中使用阵列,你只会使你的编码生活复杂化。你们需要学习的是面向目标的方案拟订。

Then you would only have to create a People object that would contain an array of Person objects.

在最简单的表格中,一个人的名字只能用一个人的名字。

People->listOfPersons[0]->fullName->familyName

or even better with getters and setters :

People->getNextPerson()->getFamilyName()

Answer 4

$index1 = $test[2];    
$index2 = $test[7];

echo $person[$index1][$index2];

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