Question

显示如何通过打电话<代码>val文档 = 文档(正文.filesDir, 文档名称)或-context. openFileOutput()来打开特定文档,但我需要在一个没有<编码>context的C图书馆开一个档案。

能否从C.A.S.A.C.A.S.R.C.A.C.A.C.S.C.A.C.R.C.A.C.R.C.C.R.C.C.R.C.R.C.R.C.C.S.R.C.C.R.C.R.C.S.R.C.R.C.R.C.C.R.C.C.R.R.R.C.C.C.R.C.C.C.S.S.C.R.S.S.C.C.S.S.S.S.S.S.R.C.C.S.C.S.S.S.S.R.S.C.R.R.R.R.M.R.R.R.M.S.R.M.C.S.M.M.S.M.M.M.M.R.R.M.M.M.M.M.M.R.M.M.M.M.M.M.M.M

Answer 1

You can simply pass your specific path as an argument to your function in C and use it with fopen.

为界定您在C中的职能,并在科特林一侧将其称作。

When you pass your String variable as argument, you need to convert it to a regular C string type (char*). So you can use this example:

JNIEXPORT void JNICALL 
Java_com_example_hellojni_HelloJni_readFile(JNIEnv *env, jobject obj,
    jstring name)
{
    const char *path= (*env)->GetStringUTFChars(env,name,0);
    // use fopen and other stuff
    // release this string when done with it
    (*env)->ReleaseStringUTFChars(env, name, str);
}

查阅您的具体目录(数据/数据/数据/清单-名称}/),不需要任何许可声明。

友情链接