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Closed 12 years ago.

I have to accept space separated integers from user but stop when i encounter a new line. For example:

3 5 7 9
23 47
6

In this example I must store 3, 5, 7, 9 in array 1, 23, 47 in array 2, 6 in array 3. Unfortunately, I don t know how to check for the end of line in C++. Please help me out.

Answer 1

通常的解决办法是使用<代码>std:getline <>/code>到行文读,然后是std:istringstream to parse each line.

Answer 2

也许不太简单,但这是一部法典。我多年来一直用在数据档案中阅读。把它当作一个星体和直径,并将退回一个有限制的星体。我通常利用它打破界限,但如果你有代表一行之末的奇迹,我就认为适用同样的原则。我要说的是,我没有写这封信,但我早就忘记了。

Split(std::string& line, std::string& splitter)
{
  std::vector<std::string> result;
  if (!line.empty() && !splitter.empty())
  {
    for (std::string::size_type offset = 0;;)
    {
      std::string::size_type found = line.find(splitter, offset);
      if (found != std::string::npos)
      {
          std::string tmpString = line.substr(offset, found-offset);
          if (tmpString.size() > 0)
          {
                  result.push_back(tmpString);
          }
          offset = found + splitter.size();
      } else {
        std::string tmpString = line.substr(offset, line.size()-offset);

       if (tmpString.size() > 0)
        {
                result.push_back(tmpString);
        }
        break;
      }
    }
  }
  return result;
}

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