Question

如何告诉网络.xml,它不应处理htc文档,因此将其留给网络服务器?

我如何能够这样做?

我正在使用Vadin,它的服务器收到所有要求,但我确实需要使用一个htc文档,以固定IE(你微软)玉米,使其更加看望。

如何做到这一点?

Vaadin Servlet

>     <servlet-mapping>
>         <servlet-name>vaadinServlet</servlet-name>
>         <url-pattern>/*</url-pattern>
>     </servlet-mapping>

Servlet

>   <servlet>
>       <servlet-name>vaadinServlet</servlet-name>
>       <servlet-class>com.vaadin.terminal.gwt.server.GAEApplicationServlet</servlet-class>
    <init-param>
>           <description>
>           Application widgetset</description>
>           <param-name>widgetset</param-name>
>           <param-value>web.googlemapwidget.Widgetset</param-value>
>       </init-param>   </servlet>

Answer 1

<servlet-mapping>
    <servlet-name>vaadinServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
    <servlet-name>default</servlet-name>
    <!-- servlet-name>staticServlet</servlet-name --> <!-- removed as suggested by raymi -->
    <url-pattern>/*.htc</url-pattern>
</servlet-mapping>

通知中,离散射线的<代码>url-pattern从/*改为/,即缺省绘图。也就是说,如果没有其他模式相匹配,则使用该服务器。 http://gigadot-blogger.blogspot.com/ 2008/09/url-patterns-in-servlet-mapping-by.html”rel=“nofollow noreferer”>quick reference 我撰写了尿素分布图。

~~You will need to define your static servlet. This depends on your servlet container. For tomcat,~~

<!-- removed as suggested by raymi -->
<!--servlet>
    <servlet-name>staticServlet</servlet-name>
    <servlet-class>org.apache.catalina.servlets.DefaultServlet</servlet-class>
</servlet-->

~~In case you do not want your staticServlet to depends on the servlet containter, read~~ this.

友情链接