Question

我有一台齐普文件上载到服务器,用于自动提取。

锡普卷宗建筑也一样:

/zip_file.zip/folder1/image1.jpg
/zip_file.zip/folder1/image2.jpg
/zip_file.zip/folder1/image3.jpg

目前,我有这一职能,可以提取所有可延伸部分的卷宗:

$zip = new ZipArchive();
    if( $zip->open($file_path) ){
        $files = array();
        for( $i = 0; $i < $zip->numFiles; $i++){
            $entry = $zip->statIndex($i);
            // is it an image?  
            if( $entry[ size ] > 0 && preg_match( #.(jpg)$#i , $entry[ name ] ) ){
                $f_extract = $zip->getNameIndex($i);
                $files[] = $f_extract;
            }
        }
        if ($zip->extractTo($dir_name, $files) === TRUE) {
        } else {
            return FALSE;
        }

        $zip->close();
    }

但是,通过使用<代码>推广功能至,它将摘录如下:

/myFolder/folder1/image1.jpg
/myFolder/folder1/image2.jpg
/myFolder/folder1/image3.jpg

是否有办法将文件夹在文件夹1中,以图人之根?

理想:

/myFolder/image1.jpg
/myFolder/image2.jpg
/myFolder/image3.jpg

PS:在冲突档案中,我只需要提取或超过档案。

Answer 1

Use this little code snippet instead. It removes the folder structure in front of the filename for each file so that the whole content of the archive is basically extracted to one folder.

<?php
$path = "zip_file.zip";

$zip = new ZipArchive();
if ($zip->open($path) === true) {
    for($i = 0; $i < $zip->numFiles; $i++) {
        $filename = $zip->getNameIndex($i);
        $fileinfo = pathinfo($filename);
        copy("zip://".$path."#".$filename, "/myDestFolder/".$fileinfo[ basename ]);
    }                  
    $zip->close();                  
}
?>

Answer 2

这里:(一) 努力管理一切事项。

$zip = new ZipArchive();
if( $zip->open($file_path) ){
    $files = array();
    for( $i = 0; $i < $zip->numFiles; $i++){
        $entry = $zip->statIndex($i);
        // is it an image?  
        if( $entry[ size ] > 0 && preg_match( #.(jpg)$#i , $entry[ name ] ) ){
            $f_extract = $zip->getNameIndex($i);
            $files[] = $f_extract; /* you man want to keep this array (use it to show result or something else) */

            if ($zip->extractTo($dir_name, $f_extract) === TRUE) {
                $solid_name = basename($f_extract);
                if(strpos($f_extract, "/")) // make sure zipped file is in a directory
                {
                    if($dir_name{strlen($dir_name)-1} == "/") $dir_name = substr($dir_name, 0, strlen($dir_name)-1); // to prevent error if $dir_name have slash in end of it
                    if(!file_exists($dir_name."/".$solid_name)) // you said you don t want to replace existed file
                        copy($dir_name."/".$f_extract, $dir_name."/".$solid_name); // taking file back to where you need [$dir_name]
                    unlink($dir_name."/".$f_extract); // [removing old file]
                    rmdir(str_replace($solid_name, "", $dir_name."/".$f_extract)); // [removing directory of it]
                }
            } else {
                 echo("error on export<br />
");
            }
        }
    }


    $zip->close();
}

Answer 3

可以通过使用<代码>zip:// syntax而不是Zip:extractTo/code>,如)手册。



你们必须贴上图像档案,然后复制:

if ($entry[ size ] > 0 && preg_match( #.(jpg)$#i , $entry[ name ])) {
  copy( zip://  . $file_path .  #  . $entry[ name ],  /root_dir/  . md5($entry[ name ]) .  .jpg );
}

如果发言,上述案文取代你的发言,并使得您的<编码>extractTo没有必要。我使用了原档案名称中的5 has,来打上独一无二的名称。由于散射碰撞很少,你不太可能有任何问题。请注意,这是一项比值沉重的义务,而你可以做如下的工作:str_replace> (/., ., .$enter [ name]),以制作新的、独特的档案名称。

全面解决办法(经修改的贵国法典):

<?php
$zip = new ZipArchive();
if ($zip->open($file_path)) {
  for ($i = 0; $i < $zip->numFiles; $i++) {
    $entry = $zip->statIndex($i);
    // is it an image?
    if ($entry[ size ] > 0 && preg_match( #.(jpg)$#i , $entry[ name ])) {
      # use hash (more expensive, but can be useful depending on what you re doing
      $new_filename = md5($entry[ name ]) .  .jpg ;
      # or str_replace for cheaper, potentially longer name:
      # $new_filename = str_replace( /. ,   , $entry[ name ]);
      copy( zip://  . $file_path .  #  . $entry[ name ],  /myFolder/  . $new_filename);
    }
  }
  $zip->close();
}
?>

友情链接