Question

我试图这样做:

def assert_record_not_found(method, object, action, params)
   begin
     method action, params
     object.find_by_id(p.id).should_not be_nil
   rescue ActiveRecord::RecordNotFound 
     assert true
   end
end

but when I do the call:

assert_record_not_found(delete, MyObject, :destroy, {:id => o.id})

鉴于删除是一种铁路检测功能,我发现一个删除的错误没有道理。

因此,是否有办法把这种方法当作论据,而不是采用这种方法本身?

Answer 1

最容易使用的是:

def assert_record_not_found(object, action, params, &block)
  begin
    block.call action, params
    object.find_by_id(p.id).should_not be_nil
  rescue ActiveRecord::RecordNotFound 
    assert true
  end
end

然后,请你说明:

assert_record_not_found(MyObject, :destroy, {:id => o.id}) do |action, params| 
  delete action, params 
end

你们也可以接受这一方法的反对,并将其交给你:

def assert_record_not_found(method, object, action, params, &block)
  begin
    method.call action, params
    object.find_by_id(p.id).should_not be_nil
  rescue ActiveRecord::RecordNotFound 
    assert true
  end
end

delete = method(:delete)
assert_record_not_found(delete, MyObject, :destroy, {:id => o.id})

使用区块的情况要大得多。

Answer 2

您不妨将Object:send作为替代办法。

达格·哈马舍尔德图书馆顶楼

class Klass
 def hello(*args)
   "Hello " + args.join(   )
 end
end
k = Klass.new
k.send :hello, "gentle", "readers"   #=> "Hello gentle readers"

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