为什么我只能以一个而不是其他价值来抓?
if(5++$var == 10){ ... }
shows a parse error
为什么我只能以一个而不是其他价值来抓?
if(5++$var == 10){ ... }
shows a parse error
使用<代码>+=。
$var += 5
您可使用复合指派操作员:
($var+=5) == 10
您可以以另一种价值计算,但该辛迪加只是不同的:
$x += 5
您要么希望5 + var = 10
,要么更明确:$var = 5
它显示了一种 par差错,因为它带有 par差错。 (作为书面文件,你重新试图在增加数字价值5后再计算)
如果你重新尝试核对5+$var
等于10用途:
if(($var + 5) == 10) ...
Because ++ is an increment operator that increments exactly by one.
$var += 5
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