Question

I ve got the following services-side pornographys: $fileName = “bin-debug/Video Source/Blackeyed Peas - The Time.flv”; Im利用以下Javascript制作带有这种录像片的运动员(使用灵活视频组件的Im)

function createPlayer(videoSource){
    document.writeln("<div id="player">");
    document.writeln("<object width="489" height="414" FlashVars=""+videoSource+"">");
    document.writeln("<param name="player" value="bin-debug/FlexPlayer.swf">");
    document.writeln("<embed src="bin-debug/FlexPlayer.swf" name="player" width="489" height="414" FlashVars=""+videoSource+"">");
    document.writeln("</embed>");
    document.writeln("</object>");
    document.writeln("</div>");               
}

职能呼吁也一样。

<script type="text/javascript">
var videoSource = "<?php echo $fileName; ?>";
    createPlayer(videoSource);
</script>

出于某种原因,运动员不打上不同的录像。也许问题在于数据和元数据交换在录像中。资料来源:具体说明。任何帮助都将受到高度赞赏。

Answer 1

愿

document.writeln("<param name=FlashVars value="+videoSource+">");

?

http://www.ohchr.org。

Then you have define the FlashVars param but it s not called in the embed

在高=“414”后插入

FlashVars=""+videoSource+""

因此

document.writeln("<embed src="bin-debug/FlexPlayer.swf" name="player" width="489" height="414" FlashVars=""+videoSource+"">");

友情链接