Question

我有这个图象:

public class Student {
       public String name;
       public School school;
}

public class School {
       public int id;
       public String name;
}
public class Data {
      public ArrayList<Student> students;
      public ArrayList<School> schools;
}

我愿将数据标同Gson编成序列,并取得以下内容:

{ "students": [{ 
                 "name":"name1",
                 "school": "1"          //the id of the scool, not its entire Json
              }],
  "school": [{                        //the entire JSON
              "id" : "1",
              "name": "schoolName"
            }]
}

为此,我必须使用学生的定制序列器,以便Gson只印刷学校的id。但对于学校而言,我必须拥有正式的序列仪。

我怎么能与只有一个Gson物体做任何事?

Answer 1

You can write a custom serializer something like this:

public class StudentAdapter implements JsonSerializer<Student> {

 @Override
 public JsonElement serialize(Student src, Type typeOfSrc,
            JsonSerializationContext context) {

        JsonObject obj = new JsonObject();
        obj.addProperty("name", src.name);
        obj.addProperty("school", src.school.id);

        return obj;
    }
}

Answer 2

当然,在你打算把这个目标编成序列的地方,你需要把这个目标添加到Gson上:

Gson gson = new GsonBuilder()
    .registerTypeAdapter(Student.class, new StudentAdapter())
    .create();
return gson.toJson([YOUR_OBJECT_TO_BE_SERIALIZED]);

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