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原标题:Extract the AST from a Ruby block

是否有可能从鲁比拉自己挖出一个路障?

我曾看过Parsree和Fluy_parser,但两者似乎都(从我刚才读到的)对Rub 1.9.2的粗略支持。 我需要的是一.9.2。

最佳回答

Ripper在盒子中被列入MRI 1.9。

ruby-1.9.2-p180 :004 > require  ripper 
 => true
ruby-1.9.2-p180 :005 > Ripper.sexp("def a; end")
 => [:program, [[:def, [:@ident, "a", [1, 4]], [:params, nil, nil, nil, nil, nil], [:bodystmt, [[:void_stmt]], nil, nil, nil]]]] 

在1.8年内,Rubya通过 trav客执行该守则,因此有可能将AST带往特定方法/锁。 在1.9条中,它不是这样;该法典首先被划为一,然后被改成麻醉药物法,然后执行。 不是来文方,也不是AST站在翻译步骤之后,后者是不可逆的;因此,你不能把海岸带入1.9块。

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