Question

因此,我有testfile。

Line one
Another line
and this is the third line

我的发言稿读到这一档案中,有点不足,我最后还有一个可以包含的变量。 of

filevar=$(cat testfile)

(这里重要的是,我不能直接查阅档案)。

我将使用该变量的内容生成一个超文本代码,而我必须做的一件事是在每个行文末尾添加<代码><br>。问题在于,在我瓦尔似乎有过任何电子运输工具:

echo $filevar
Line one Another line and this is the third line

How do I read the file properly to keep the EOLs? Once I have that I can simply sed s/$/<br>/g, but till then...

感谢!

Answer 1

http://www.ohchr.org。这将发出一个单一的论点来回应,然后,你可以把这一论点推向前进。

顺便说一句,将视之为3行,因此你不需要这种选择。与我合作(现金和cy子):

echo "$filevar" | sed  s/$/<br>/

Answer 2

如何改变爱幼学校?

#!/bin/bash

IFS=""
filevar=$(cat test)
echo $filevar

产出:

Line one
Another line
and this is the third line

Answer 3

我无法理解,为什么你需要把档案翻译成变数。为什么不只要求你这样做:

sed  s|$|<br/>|  testfile

<><>UPDATE:

If you really want to get the EOL back in your variable. Try this (notice the quotes):

echo "$filevar"

但我仍然可以理解,why You can cat。查阅文件

作为一个解决办法,我要提出以下文字:

while read LINE
do
  echo ${LINE}  <br />    # Implement your core logic here.
done < testfile

Answer 4

您需要制定<代码>IFS的变量,以仅包含一条新线,然后参照<代码>.var>/code><> 可变>,无<>>>。

$ filevar= Line one
Another line
and this is the third line 

$ for word in $filevar; do echo "$word<br>"; done
Line<br>
one<br>
Another<br>
line<br>
and<br>
this<br>
is<br>
the<br>
third<br>
line<br>

$ for word in "$filevar"; do echo "$word<br>"; done
Line one
Another line
and this is the third line<br>

$ (IFS=$ 
 ; for word in $filevar; do echo "$word<br>"; done)
Line one<br>
Another line<br>
and this is the third line<br>

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