Question

我发现,“我”上的所有文字都与“ Java”阵列中的任何字相对应,并强调这些字句(在特别标签上加以更正)。这样做最容易的方式? 页: 1

Answer 1

不是完美的,而是简单的工作:

var regex = /(Hello|Goodbye)/g;

$( * ).each(function() {
    var $this = $(this);
    var text = $this.text();
    if (regex.test(text)) {
        $this.html(
            $this.html().replace(regex,  <span>$1</span> )
        );
    }
});

rel=“nofollow> http://jsfiddle.net/pdWAn/。

Answer 2

B. 这种方法

highlightWord(["text1", "text2"]);


function highlightWord(searchArray, container)
{
  var bodyText;
  if(container)
     bodyText = container.html();
  else
     bodyText = $(document.body).html();

  container = container || $(document.body);

  for (var i = 0; i < searchArray.length; i++) {
    bodyText = doHighlight(bodyText, searchArray[i]);
  }

  container.html(bodyText);

  return true;
}

function doHighlight(bodyText, searchTerm) 
{

    var highlightStartTag = "<span style= color:blue; background-color:yellow; >";
    var highlightEndTag = "</span>";

  var newText = "";
  var i = -1;
  var lcSearchTerm = searchTerm.toLowerCase();
  var lcBodyText = bodyText.toLowerCase();

  while (bodyText.length > 0) {
    i = lcBodyText.indexOf(lcSearchTerm, i+1);

    if (i < 0) {
      newText += bodyText;
      bodyText = "";
    } else {
      if (bodyText.lastIndexOf(">", i) >= bodyText.lastIndexOf("<", i)) {
        if (lcBodyText.lastIndexOf("/script>", i) >= lcBodyText.lastIndexOf("<script", i)) {
          newText += bodyText.substring(0, i) + highlightStartTag + bodyText.substr(i, searchTerm.length) + highlightEndTag;

          bodyText = bodyText.substr(i + searchTerm.length);

          lcBodyText = bodyText.toLowerCase();

          i = -1;

        }

      }

    }

  }

  return newText;
}

友情链接