Question

我试图有一个用户界定的游戏地图清单。由于我不知道设计时有多少地图将出现在阵列中,因此我试图动态地创造新的变量,以控制这些地图。这是否可行? 我的失败尝试:

<?php
$maplist=array("map1.aamap.xml","map2.aamap.xml"); //edit this list with your maps
$rounds = 3;                 //times to play each map
/*======No need to edit below========*/
global $last;  //store the last played map               
class Map
{
    public $difficulty;
    public $played;  //amount of times played
}
foreach($maplist as $i => $element)
{
    $element = $map[$i];
    $map[$i] = new Map();
}
//snipped other code here
$map[$i]->$played = $x++;  //increment the times played counter <-- FAILS HERE
?>

Parser指出:Fatal差错: 不得获取空闲财产

这样做是否可行?

Answer 1

您的法典中有一些错误:

<?php
$maplist=array("map1.aamap.xml","map2.aamap.xml"); //edit this list with your maps
$rounds = 3;                 //times to play each map
/*======No need to edit below========*/
global $last;  //store the last played map

既然你在此具有全球范围,而不属于职能范围,就不需要<条码>全球。

class Map
{
    public $difficulty;
    public $played;  //amount of times played
}
foreach($maplist as $i => $element)
{
    $element = $map[$i];

这里是否有任何法典缺失? 您不使用<条码>代号,因此不需要这一转让。

    $map[$i] = new Map();
}
//snipped other code here
$map[$i]->$played = $x++;  //increment the times played counter <-- FAILS HERE

进入成员变量的星号为:$object->variable,而不是$object->$variable。后者将评价<代码>可变,并将该数值作为变量名称(例如,如果$variable = “foo”,这将试图查阅$object->foo。

使用<代码> 地图[$i]->meted =x++;代替。

Answer 2

When accessing the properties of a class, you don t want to use the $ in front of the property name itself.

http://www.o.un.org。致命错误: 不能从空置财产错误中获取。

Answer 3

如果你希望:

public function __get($name)
{
...
}

public function __set($name, $value)
{
...
}

members/a>

在这些职能中,你可以将数据储存在某些内部阵列结构中。

Answer 4

You don t have to use the $ when accessing properties of an instance. Simple use $map[$i]->played. Have a look on the OOP basics.

友情链接