Question

I am trying to write a benchmark program that takes about 20 minutes to complete because the actual functions need to be called at least 50 times.

我使用了以下法典:

struct timeval start, end;
long mtime, seconds, useconds;
gettimeofday(&start, NULL);
usleep(2000);
gettimeofday(&end,NULL);
seconds =end.tv_sec - start.tv_sec;
useconds=end.tv_usec - start.tv_usec; 
(mtime>1000)?cout<<"elapsed time in seconds:"<<setprecision(8)<<mtime/1000<<"seconds
":cout<<"elapsed time in milliseconds: "<<setprecision(3)<<mtime<<" milliseconds
";

但我必须写这封信,使产出产生最佳单位,用于过去的时间,并在这些单位展示成果。我如何根据要求修订上述准则? th!

Answer 1

我的猜测是,你的“最佳单位”要求基本上是“人类可使用的单位”。如果是,需要时间,

millisecs mod 1000 gives number of milliseconds
millisecs div 1000 gives seconds (where div is integer division)
seconds mod 60 gives number of seconds
seconds div 60 gives minutes

and so on.

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