Question

从事这一示范协会类任务。基本协会在发挥作用,但与“类别”网页的观点无关。

类别产出应为(类别)

Dish-ID
Dish-Title
Restaurant-Title <= HOW DO I GET THIS VALUE?

rules: - dish belongs to one category - same dish can be in multiple restaurants

class Category < ActiveRecord::Base
  has_many :dishes
end

class Dish < ActiveRecord::Base
  belongs_to :category
end

class Restaurant < ActiveRecord::Base
  has_and_belongs_to_many :dishes
end

class DishRestaurant < ActiveRecord::Base
  has_many  :restaurants
  has_many  :dishes
end

主计长

def show
  @category = Category.find(params[:id])
  @dishes = @category.dishes
  // RESTAURANT TITLE ??

respond_to do |format|
  format.html # index.html.erb
  format.xml  { render :xml => @category }
end

Category View: <%= debug @dishes %>

任何方面都会有所帮助。

thanks

pete

Answer 1

Define you models properly:

class Dish < ActiveRecord::Base
  belongs_to :category
  has_and_belongs_to_many :restaurants
end

class Restaurant < ActiveRecord::Base
  has_and_belongs_to_many :dishes
end

This would use the implicit join table names "dishes_restaurants". You only need a join model is you store some join specific information, like price of the dish in the restaurant. In which case you models should be like:

class Dish < ActiveRecord::Base
  belongs_to :category
  has_many :dish_restaurants
  has_many :restaurants, through => :dish_restaurants
end

class Restaurant < ActiveRecord::Base
  has_many :dish_restaurants
  has_many :dishes, through => :dish_restaurants
end

class DishRestaurant < ActiveRecord::Base
  belongs_to  :restaurant
  belongs_to  :dish
end

无论你采取什么做法,你都可以填写<条码>dish.restaurants,以检索为迪斯拉发服务的餐馆名单。

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