Question

我试图用山角地图APIC来打上方向。我很想创造ur,得到JSON的回复,然后审查旅行时间的回复。在我创立了JSON目标之后,我难以浏览。对我来说,这表明,我要么听了回答,要么把JSON的物体拿走。我很想知道,你能否坐在我从网上的辅导员那里走到一起的手法和法典中。

该守则意在得到答复。它环绕了审判/副渔获物,没有引起任何错误。

      String stringUrl = <URL GOES HERE>;

      URL url = new URL(stringUrl);
      HttpURLConnection httpconn = (HttpURLConnection)url.openConnection();
      if (httpconn.getResponseCode() == HttpURLConnection.HTTP_OK)
      {
          BufferedReader input = new BufferedReader(new InputStreamReader(httpconn.getInputStream()),8192);
          String strLine = null;
          while ((strLine = input.readLine()) != null)
          {
              response.append(strLine);
          }
          input.close();
      }
      String jsonOutput = response.toString();

该守则旨在根据

        JSONObject jsonObject = new JSONObject(jsonOutput);
        JSONObject routeObject = jsonObject.getJSONObject("routes");
        JSONObject legsObject = routeObject.getJSONObject("legs");
        JSONObject durationObject = legsObject.getJSONObject("duration"); 
        String duration = durationObject.getString("text");

I m 在第二组第二行捕获一名JSON例外。谁能帮助解决这一问题? 或者说,获得同样数据的方法比较简单?

www.un.org/Depts/DGACM/index_spanish.htm EDIT:通过这里的第一个有益答案(从速),后半部分现为。

    JSONObject jsonObject = new JSONObject(responseText);
    JSONArray routeObject = jsonObject.getJSONArray("routes");
    JSONArray legsObject = routeObject.getJSONArray(2); ***error***
    JSONObject durationObject = legsObject.getJSONObject(1);
        String duration = durationObject.getString("text");

但是,它仍然 throw着一名JSON例外,只是在第三行之后。我相信,这非常容易确定,但我确实会感谢一些帮助。

JSON案的相关部分如下:

{
   "routes" : [
      {
         "bounds" : {
            "northeast" : {
               "lat" : 34.092810,
               "lng" : -118.328860
            },
            "southwest" : {
               "lat" : 33.995590,
               "lng" : -118.446040
            }
         },
         "copyrights" : "Map data ©2011 Google",
         "legs" : [
            {
               "distance" : {
                  "text" : "12.9 mi",
                  "value" : 20807
               },
               "duration" : {
                  "text" : "27 mins",
                  "value" : 1619
               },

Answer 1

"routes" is an array, instead of using getJSONObject, use getJSONArray

"legs" is an array also.

JSONObject jsonObject = new JSONObject(responseText);

// routesArray contains ALL routes
JSONArray routesArray = jsonObject.getJSONArray("routes");
// Grab the first route
JSONObject route = routesArray.getJSONObject(0);
// Take all legs from the route
JSONArray legs = route.getJSONArray("legs");
// Grab first leg
JSONObject leg = legs.getJSONObject(0);

JSONObject durationObject = leg.getJSONObject("duration");
String duration = durationObject.getString("text");

Answer 2

I was also trying to use the Direction Api of Google in Android. So I made an open source project to help doing that. You can find it here:https://github.com/MathiasSeguy-Android2EE/GDirectionsApiUtils

How it works, definitly simply:

public class MainActivity extends ActionBarActivity implements DCACallBack{
/**
 * Get the Google Direction between mDevice location and the touched location using the     Walk
 * @param point
 */
private void getDirections(LatLng point) {
     GDirectionsApiUtils.getDirection(this, startPoint, endPoint, GDirectionsApiUtils.MODE_WALKING);
}

/*
 * The callback
 * When the directions is built from the google server and parsed, this method is called and give you the expected direction
 */
@Override
public void onDirectionLoaded(List<GDirection> directions) {        
    // Display the direction or use the DirectionsApiUtils
    for(GDirection direction:directions) {
        Log.e("MainActivity", "onDirectionLoaded : Draw GDirections Called with path " + directions);
        GDirectionsApiUtils.drawGDirection(direction, mMap);
    }
}

友情链接