Question

我有一阵列,见下文。

NSMutableArray *myArray=[[NSMutableArray alloc]initWithObjects:@"45 x 2",@"76 x 3",@"98 x 3", nil];

现在我想到的是,在另一阵列中,所有具有“x”性质的权利。这是需要从上述阵列中包含以下要素的阵列:@”2,@”3“。

How can i achieve this?? thanks..

Answer 1

NSMutableArray *myArray=[[NSMutableArray alloc]initWithObjects:@"45 x 2",@"76 x 3",@"98 x 3", nil];
NSMutableArray *tempArray = [NSMutableArray array];
for(NSString *string in myArray)
{
    NSArray *array = [string componentsSeparatedByString:@"x"];
    if(array.count > 1)
        [tempArray addObject:[array objectAtIndex:1]];
}

Answer 2

    NSMutableArray *myArray=[[NSMutableArray alloc]initWithObjects:@"45 x 2",@"76 x 3",@"98 x 3", nil];
    NSMutableArray *suffixArray = [NSMutableArray array];
    for (NSString *el in myArray)
    {
        NSRange range = [el rangeOfString:@"x"];
        if (range.location == NSNotFound) [prefixArray addObject:@""];
        NSString *suffix = [el substringFromIndex:range.location+range.length];
        [suffixArray addObject:suffix];
    }

Answer 3

选择住所并实现这一目标

NSArray *splitedString = [[myArray objectAtIndex:indexVal] componentsSeparatedByString: @"x"];


    if ([splitedString count]>1)
{
            NSString *prefixString=[splitedString objectAtIndex:1];
            //Add this to ur new array
}

友情链接