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What is the difference between an int and a long in C++?
difference in long vs int data types in C++
c++是中长期数据类型之间的偏差。 改写以下法典:
int _tmain(int argc, _TCHAR* argv[])
{
cout<<"Int_Max = "<<INT_MAX<<endl;
cout<<"Int_Min = "<<INT_MIN<<endl;
cout<<"Long_Max = "<<LONG_MAX<<endl;
cout<<"Long_Min = "<<LONG_MIN<<endl;
}
结果是......
Int_Max = 2147483647
Int_Min = -2147483648
Long_Max = 2147483647
Long_Min = -2147483648
我很混淆。
根据该标准,<代码>int保证至少为16个比值,long至少为32个比值。 在大多数32位汇编者中,两者都是相同的,均为32个。 但是,由于还有64、16、甚至8个实体的汇编者,你就没有这样做了。
在32个轨道系统中,<代码>int和long之间通常没有任何区别。 如果你想要在32个轨道系统上采用64个轨道数据类型,则尝试 长期。
如果你想要保证数据类型的规模,你就应当使用星体中的类型(需要C++0x支持g++,通过汇编-std=c++0x 而得到这种支持)。 例如,你将使用t32_t and int64_t,而不是 in或长。 如果你想要一个没有签名的数据类型,就只会增加一个起点。 页: 1 这是一种16倍的未签名的分类账。
然而,你只应当利用这些空间。 否则,“int”一般更为可取。
果园:至少8个轨道:等于一个单位
简言之:至少16条轨道:至少宽度
注:至少有16个轨道:至少范围很广
long : at least 32 bits : at least as wide as int
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