Question

因此,有过滤信函和/“:=如何允许-?

#include <boost/regex.hpp>
#include <boost/algorithm/string/regex.hpp>

std::string filter_args(std::string args)
{
    std::cout << boost::erase_all_regex_copy(args, boost::regex("[^a-zA-Z0-9="/.: ]+")); 
    return boost::erase_all_regex_copy(args, boost::regex("[^a-zA-Z0-9="/.: ]+"));
}

Answer 1

。

You can specify a character class, by enclosing a list of characters in [], which will match any character from the list. If the first character after the "[" is "^", the class matches any character not in the list. Within a list, the "-" character specifies a range, so that a-z represents all characters between "a" and "z", inclusive. If you want either "-" 或 "]" itself to be a member of a class, put it at the start of the list (possibly after a "^"), 或 escape it with a backslash. "-" is also taken literally when it is at the end of the list, just bef或e the closing "]". (The following all specify the same class of three characters: [-az], [az-], and [a-z]. All are different from [a-z], which specifies a class containing twenty-six characters, even on EBCDIC-based character sets.) Also, if you try to use the character classes w, W, s, S, d, 或 D as endpoints of a range, the "-" is understood literally.

因此:

boost::erase_all_regex_copy(args, boost::regex("[^a-zA-Z0-9="/.: -]+"))

或

boost::erase_all_regex_copy(args, boost::regex("[^a-zA-Z0-9=\-"/.: ]+"))

(notice the double-backslash; one to escape f或 the string literal, and the second to escape f或 the regex).

I recommend the f或mer.

Always check out the documentation as your first p或t of call!

Answer 2

以<条码>取代。这应当奏效。 <代码>-。

你实际上将不得不做两次工作。 <>条码>-<> 越出<条码><>/代码>,越出第二个时间越出<条码>-。

Answer 3

留在方括号内,如<代码>[^a-zA-Z0-9=”/.:-]。

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