例如,我有770份许可。 当我做时:
ln -s foo.sh bar.sh
联系酒吧有2777份许可。 为什么如此? 我认为,他们打算继承吗?
例如,我有770份许可。 当我做时:
ln -s foo.sh bar.sh
联系酒吧有2777份许可。 为什么如此? 我认为,他们打算继承吗?
关于象征性联系的许可基本上不重要。 他们通常为777人,经修补。
symlink(
说:
The values of the file mode bits for the created symbolic link are unspecified. All interfaces specified by POSIX.1-2008 shall behave as if the contents of symbolic links can always be read, except that the value of the file mode bits returned in the
st_mode
field of the stat structure is unspecified.
POSIX提供lchown(。 系统电话:不提供<><>>条码>lchmod(>/s>功能。
(关于我的MacOS X 10.7.1, umask 022, 新近创建的Symlink以755份许可告终;与Mumask 002一样,许可有效期为775。) 因此,有770 700条许可等许可的链接可能会准确无误;许可环境仍然非实质性,不影响连接线的可用性。
关于林丹(RHEL 5, ×86_64;kernel 2.6.18-128.el5),我只看到在 s立时有777次许可:
$ (ls -l xx.pl; umask 777; ln -s xx.pl pqr; ls -l xx.pl pqr)
-rw-r--r-- 1 jleffler rd 319 2011-09-05 22:10 xx.pl
lrwxrwxrwx 1 jleffler rd 5 2011-09-21 10:16 pqr -> xx.pl
-rw-r--r-- 1 jleffler rd 319 2011-09-05 22:10 xx.pl
$
我认为,在一个小小小小小小块中,马斯克环境不是永久的。
On MacOS X (10.7.1), I get to see variable permissions on a symlink:
$ (ls -l xxx.sql; umask 777; ln -s xxx.sql pqr; ls -l xxx.sql pqr)
-rw-r--r-- 1 jleffler staff 1916 Jun 9 17:15 xxx.sql
ls: pqr: Permission denied
l--------- 1 jleffler staff 7 Sep 21 10:18 pqr
-rw-r--r-- 1 jleffler staff 1916 Jun 9 17:15 xxx.sql
$
Note that this is the same command sequence (give or take the file name) linked to.
On MacOS 页: 1 指挥权可选择<代码>-h,以改变对电离层连接本身的许可:
-h
If the file is a symbolic link, change the mode of the link itself rather than the file that the link points to.
On MacOS X,关于link关问题的许可;除非你读过关于link子的许可(或你重生)。 因此,上文<代码>ls输出的错误。 http://www.ohchr.org。 Ec.
关于MacOS X,chmod -h 100 pqr
(execute)允许我使用链接(cat pqr
work),但不能读到链接。 相比之下,<代码>chmod -h 400 pqr 允许我阅读链接并使用链接。 为了完整起见,chmod -h 200 pqr
请允许我利用这一联系,但不要阅读。 我假定,未经正式测试,类似规则适用于群体和其他群体。
On MacOS 因此,在X时,看上或写上短程的许可似乎允许你通常使用,但仅凭执行许可就意味着,即使你能够在链接的另一端查阅档案(或大概是目录)。
The MacOS X behaviour is an extension of the behaviour mandated by POSIX - or deviation from the behaviour mandated by POSIX. It complicates life slightly. It means that you have to ensure that anyone who is supposed to use the link has permission to do so. This is normally trivial (umask 022
means that will be the case).
基础系统呼吁在澳门建立<代码>chown-h 页: 1
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