Question

排在桌面上不是一个问题。

问题在于通过表格进行对比,同时将另一条拖到具有不同价值的同一行中。如何做到这一点?

- going through #tblView tbody tr.class

        - to find through all row for second td and see whether the .text() is "completed"
                - if yes
                        - then third td s span s inner text set to "bingo"
                - else
                        - do nothing
                - end


<table id="tblView">

<tbody>

<tr class="class">

<td>completed</td>
<td></td>
<td></td>

</tr>

<tr class="class">

<td>not yet</td>
<td></td>
<td></td>

</tr>

</tbody>

</table>

Answer 1

Try -

$("#tblView tbody tr.class").each(function() {
    if ($(this).find("td:eq(1)").text() === "completed") $(this).find("td:eq(2)").text( bingo ); 
})

Demo - 。

友情链接