Question

如果我使用<代码>时,则我获得的产出与产出一样。

$ time sleep 1

real    0m1.003s
user    0m0.000s
sys     0m0.000s

然而,如果我用双管书写,产出就是这样。

0.00user 0.00system 0:01.00elapsed 0%CPU (0avgtext+0avgdata 2176maxresident)k
0inputs+0outputs (0major+179minor)pagefaults 0swaps

I already found this post, but what I want is to use time in a script, while still getting the same output as if I was using it in a shell.

Answer 1

页: 1

$ echo "time -p sleep 1" > x1

$ bash x1
real 1.01
user 0.00
sys 0.00

Answer 2

0.00user 0.00system 0:01.00elapsed 0%CPU (0avgtext+0avgdata 2176maxresident)k
0inputs+0outputs (0major+179minor)pagefaults 0swaps

......是全球疫苗联盟外部版本tor 。

real    0m1.003s
user    0m0.000s
sys     0m0.000s

...is the default output produced by the bash builtin time. This builtin version of time is a bash extension: a POSIX-compliant shell is not required to provide a builtin version of time.

然而, POSIX确实规定了一种外部<代码> 时间通用,该代码可选择<代码>-p,以产生另一种产出格式:

real 1.01
user 0.00
sys 0.00

...and the bash builtin also accepts the -p option to produce the same output format.

<代码>bash 封面应当完全用字母进行,条件是文字实际上由<条码>b<>>> >:

$ cat time.sh #!/bin/bash time sleep 1 $ ./time.sh real 0m1.001s user 0m0.000s sys 0m0.000s $

因此,您的文字似乎正在援引外部效用,而不是<条码>bash。

其最可能的原因是:

your script says #!/bin/sh rather than #!/bin/bash; and

the /bin/sh on your machine is not actually bash, but a more lightweight POSIX-compliant shell without the bash extensions (as found on some Linux distributions these days).

The solution is to ensure that the script specifically invokes bash by using #!/bin/bash if it relies on bash extensions.

Answer 3

The difference is that output is not going to terminal when piped.

做冰布所需的终端代码在档案库中不可行。

What did you want to achieve? If you intend to have the screenshot have a look at script

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