Question

I would like to compare 2 "multidimensional" arrays (arrays nested in arrays).

var old_dataArray=new Array(("id-2", "message", "user"), ("id-1", "message", "user"), ("id-0", "message", "user"));
var new_dataArray=new Array(("id-3", "message", "user"), ("id-2", "message", "user"), ("id-1", "message", "user"));

在此情况下,我要得到“旧数据阿雷”而不是“新数据阿雷”中包含的阵列(“id-3”、“message”、“user”)。

I ve tried with the array_diff function presented here. http://phpjs.org/functions/array_diff:309 But it doesn t really work !.

Answer 1

根据我的理解,你想从新数据中获取所有阵列,这些阵列不是旧数据,假定如果每个要素(id-n要素)中的第一个要素相同,那么其他阵列也是如此。你可以这样做:

// create an array to store our results:
var results = new Array();

// loop through new_dataArray:
outerloop:
for (var i = 0; i < new_dataArray.length; ++i) {

    // loop through old_dataArray to compare the i th element
    // in new_dataArray with each in old_dataArray:
    for (var j = 0; j < old_dataArray.length; ++j) {

        // check if the ids are the same
        if (new_dataArray[i][0] == old_dataArray[j][0])
            // yes it s there, so move on to the next element of new_dataArray
            continue outerloop;

    }

    // if we get here, continue outerloop; was never called so 
    // this element is not in old_dataArray
    results.push(new_dataArray[i]);

}

// now results contains all arrays that are in new_dataArray 
// but not in old_dataArray

EDIT:然而,如果你想要每个阵列的所有要素都平等,而不仅仅是第一个(前)要素,则使用:

// create an array to store our results:
var results = new Array();

// loop through new_dataArray:
outerloop:
for (var i = 0; i < new_dataArray.length; ++i) {

    // loop through old_dataArray to compare the i th element
    // in new_dataArray with each in old_dataArray:
    innerloop:
    for (var j = 0; j < old_dataArray.length; ++j) {

        // check if the arrays are the same size:
        if (new_dataArray[i].length != old_dataArray[j].length)
            // no, so they must be different
            continue innerloop;

        // check if the arrays have the same values
        for (var k = 0; k < old_dataArray[j].length; ++k) {

            if (new_dataArray[i][k] != old_dataArray[j][k])
                // the k th element is different
                continue innerloop;
        }

        // if we get here, then we have found a match, so move on
        continue outerloop;

    }

    // if we get here, continue outerloop; was never called so 
    // this element is not in old_dataArray
    results.push(new_dataArray[i]);

}

// now results contains all arrays that are in new_dataArray 
// but not in old_dataArray

Answer 2

var old_dataArray = [["id-2", "message", "user"], ["id-1", "message", "user"], ["id-0", "message", "user"]];
var new_dataArray = [["id-3", "message", "user"], ["id-2", "message", "user"], ["id-1", "message", "user"]];

var result = [];

for (var i = 0; i < new_dataArray.length ; i++) {
    var isInOldArray = false;
    console.log(new_dataArray[i][0]);

    for (var j = 0; j < old_dataArray.length; j++) {
         if (old_dataArray[j][0] === new_dataArray[i][0]) {
             isInOldArray = true;
             break;
         };
    };

    if (!isInOldArray) {
        result.push(new_dataArray[i]);
    };
};

alert(result);

友情链接