Question

我正在使用xslt 1.0,正试图将目前的日期和时间印在我的节点上。样本Xslt如下:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:tcm="http://www.tridion.com/ContentManager/5.0" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:em="http://www.emirates.com/tridion/schemas" xmlns:tcmse="http://www.tridion.com/ContentManager/5.1/TcmScriptAssistant" exclude-result-prefixes="em xlink tcmse tcm">
  <xsl:output method="xml" version="1.0" encoding="UTF-16" indent="yes"/>

  <!-- Common XSLT Templates-->
  <xsl:include href="tcm:228-190524-2048"/>
  <!-- root match-->
  <xsl:template match="root">
    <sitedata>
      <resources>        
        <PublishedDate>
          <xsl:value-of select="$publishedDate"/>
        </PublishedDate>
      </resources>     
    </sitedata>
  </xsl:template>

In above XSLT, in the place of $publishedDate 我想系统目前的日期和时间

请建议!

Answer 1

XSLT 1.0 does not provide any standard way to get the current date/time. You can call an extension function to do it (depends on your processor), or you can pass it to the stylesheet as the value of a parameter.

Answer 2

www.un.org/Depts/DGACM/index_spanish.htm http://www.microsoft.com/download/en/details.aspx?displaylang=en&id=21714“rel=“nofollow”>msxsl.exetor-lineutil>/strong>(用于MSXML):

XSLT Code (testParams.xsl):

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:param name="vDate" select="xyz"/>

 <xsl:template match="/">
  "<xsl:value-of select="$vDate"/>"
 </xsl:template>
</xsl:stylesheet>

XML文件(t.xml)(fake, 被忽视):

<t/>

<>Command-line

msxsl t.xml testParams.xsl -o con vDate= %date%

<>Result:

"Sun 10/02/2011"

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