Question

是否有办法将这些办法结合起来?

$("#demo1Btn").mopTip({ w :200, style :"overClick", get :"#demo1"});
$("#demo2Btn").mopTip({ w :200, style :"overClick", get :"#demo2"});
$("#demo3Btn").mopTip({ w :200, style :"overClick", get :"#demo3"});
$("#demo4Btn").mopTip({ w :200, style :"overClick", get :"#demo4"});
$("#demo5Btn").mopTip({ w :200, style :"overClick", get :"#demo5"});

Thnx

Answer 1

for (var i = 1; i < 6; i++) {
  $("#demo" + i + "Btn").mopTip({ w :200, style :"overClick", get :"#demo" + i});
}

比较清洁

Answer 2

是的,你可以把所有班级/班级安排在同一职能上,但只是与 com分开。

$("#demo1Btn, #demo2Btn, #demo3Btn, #demo4Btn, #demo5Btn").mopTip({ w :200, style :"overClick", get :$(this).attr( id ).replace( Btn ,  )});

This should work!

Answer 3

明显有:

$( div[id^="demo"][id$="Btn"] ).mopTip({ w :200, style :"overClick", get :this.id});

将选择<代码>id从“demo”开始、以“btn”结束、this.id 应找到相关要素<代码>id,并将之分派至get参数。

Answer 4

Use the starts-with selector and an each loop

$("[id^= demo ]").each(function(){
    $(this).mopTip({ w :200, style :"overClick", get :"#demo1"});
});

友情链接