I m 试图取代外部模块接口的类型参数,该模块在 我的法典中有以下内容: 没有哪类违约,我就有一个<代码>。 Foo的所有申报必须具有相同的类型参数:误差。 可以理解。 So my goal is to replace the original interface entirely with one that extends it, rather than augment it. That is, functionally accomplish this pseudocode: 目前,我的解决办法是建立一个单独的接口,使用模块增强,以改变其Namespace的返回类型,但我更喜欢只有一个接口。 Is there a better way? 感谢!.d.ts
上宣布如下:declare namespace TheirNamespace {
interface Foo<GenericType = any> {
}
}
declare global {
export namespace TheirNamespace {
export interface Foo<GenericType = any, ExtraType extends object = never> {
}
}
TheirNamespace.Foo = MyInterfaceThatExtendsFoo
, such that anything using Foo
will actually point at my interface instead (for IntellIsense).
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