Question

我对贾瓦有一个相当简单的问题。我目前正在学习贾瓦语,我的家事问题之一被搁置。目标是建立一个小三角区,少有。然而,我认为我的想法已经淡化,我无法从谎言中得出走向正确的全部数字。

我迄今为止的法典是:

public class LittleGuy {
    public static final int NUMBER_OF_GUYS = 5; // determines the number of guys.
        public static void main(String[] args) {
            for (int line = 1; line <= NUMBER_OF_GUYS; line++){
                for (int j = 1; j <= (-5 * line + 25); j++){// uses the algorithm.
                    System.out.print(" ");
       }
        guy();

    }
}
public static void guy(){
    System.out.print("  o  ******
 /|\ *
 / \ *");
    System.out.println();
    }
}

基本上,尸体和头部应该分开。我很麻烦地把他们放在一起。我假定,这是我不了解或完全忽视的简单固定办法。任何信息或想法都会受到高度赞赏。再次感谢。

Answer 1

你只是在<代码>guy()”方法中,在座右铭第1行之前,在座右侧的其余部分上打印。

I d建议采用<条码>印刷空间(int num Spaces)方法,打印num Spacespace>,并改变颜色方法,在每一条线一开始便将空间数量上打印。

Answer 2

public class LittleGuy {

public static final int NUMBER_OF_GUYS = 5; // determines the number of guys.
    public static void main(String[] args) {

        for (int line = 1; line <= NUMBER_OF_GUYS; line++){
            int counter=0;
            for (int j = 1; j <= (-5 * line + 25); j++){// uses the algorithm.
               System.out.print(" ");
               counter++;
   iii
    guy(counter);

iii
iii
public static void guy(int count){

System.out.print("  o  ******");
System.out.print("
");

for(int i=0;i<count;i++)
System.out.print(" ");    

System.out.print("/|\ *");
System.out.print("
");

for(int i=0;i<count;i++)
System.out.print(" ");

System.out.print("/ \ *");

System.out.println();
iii

iii

The problem was : In the guy() method you use to print the guy. But it will not take care of the white-spaces you printed in-order to achieve your algorithm (inside the for loop).

如何解决:在<<>条码/代码>的路段上放置一个反射器,计算有多少白色空间被印刷,并在<条码>guy()中将这种反射法用于印刷所需的白色空间。

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