i ve seen a lot of other questions touch on the subject but nothing as on topic as to provide an answer for my particular problem. Is there a way to search an array and return values within a given range... for clarity I have one array = [0,5,12] I would like to compare array to another array (array2) using a range of numbers. Using array[0] as a starting point how would I return all values from array2 +/- 4 of array[0].
在这一特定情况下,从2阵列返回的人数将在4-4和4之间。
感谢Ninjas的帮助。
构建一个范围,即你的具体目标±4,然后使用https://ruby-doc.org/core/Evidable.html#method-i-select” rel=“nofollow noretinger”> 无数可读的#select<>/code http://ruby-doc.org/french/Range.html
例如,让我们看一看一阵列中的11±4号,其中包括1至100号(包括):
a = (1..100).to_a
r = 11-4 .. 11+4
a.select { |i| r.include?(i) }
# [7, 8, 9, 10, 11, 12, 13, 14, 15]
如果你不关心在你的产出中保持秩序,而且你不会重复你的工作,你可以这样做:
a & (c-w .. c+w).to_a
Where c is the center of your interval and w is the interval s width. Using Array#& treats the arrays as sets so it will remove duplicates and is not guaranteed to preserver order.
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