Question

我试图完成我必须完成的任务,即在像种族这样的艰难时刻计算第二秒。在格式上打上头盔。第二次计算结果为时数和秒。这是非目标方案拟订的开端课程,因此,我使用的守则必须是简单的,没有额外的班级来处理时间。我之所以要问,是因为我的计算有时得出错误的结果。我这样做了:

totalAmountOfSecondsPerHour = (endHour - startHour) * 3600;
totalAmountOfMinutesPerMinutes = Math.abs((endMinutes - startMinutes) * 60);
totalAmountOfSeconds = Math.abs(endSeconds - startSeconds));

我利用Math.abs去除负面数字。

得出总数额,我增加所有变量。最后,我这样说:

resultHour = totalAmountOfSeconds / 3600;
rest totalAmountOfSeconds % 3600;

resultMinutes = rest / 60;
resultSeconds = rest % 60;

当我起步时,如1 50030,最后时间为165015,结果为1小时50分15秒。如果是45秒,我会认为应该更加正确吗? 我的计算可能是错误的? 是否有更好的办法,或者我是否可以修改或简化我的准则,从而产生正确的结果? 给予一些帮助! 感谢!

Answer 1

这是因为你使用Math.abs()

让我举一个小例子: 时间从00:00:59开始,2秒在0:01:01时结束

totalAmouneOfMinutesPerMinutes = Math.abs(1 - 0) * 60  = 60
totalAmountOfSeconds = Math.abs(1 - 59) = 58

因此,第60+58 = 118秒而不是2秒。如果我们去除Math.abs,我们就有:

totalAmouneOfMinutesPerMinutes = (1 - 0) * 60  = 60
totalAmountOfSeconds = (1 - 59) = -58

60 + (-58) = 2秒(如 su)。

Answer 2

您的二人基本上都在做事。

15 - 30 = -15 ABS(-15) = 15

因此,你的问题是。

你也许想试图让国际自由论坛尝试二者是消极的。

Answer 3

以起步时间为例:1:10:10和结尾时间1:11:05显然区别应为55秒。

But you do abs(5-10) for the seconds and get 5 seconds. And you get 1 minute 5 seconds.

You have two approaches to fix this: Get rid of the abs and instead if you get a negative result add that (negative) amount to the amount of the next higher value.

So in the example instead of adding abs(-5) to 1 minute you add -5 to 1 minute, resulting in 0 minutes and 55 seconds.

While this will work it will get quite confusing.

A better approach would be: convert start and end time into seconds. Take the difference. Convert the result back into hours, minutes and seconds

Answer 4

Those Math.abs tripped you up... Convert the time to seconds, do substraction and then convert back to hhmmss format.

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