我有一句空话,我在一些职位上显示风向,arrow亮,但其他阵地则lated平。 这里是使形象化的法律:
public class DialView extends View {
private Context mContext;
private Bitmap mArrow;
private WeatherDataModel mWdm;
private float iters = 10.0f;
private static float previousAngle = 0.0f;
private int mHourIndex = 0;
private boolean isHourly = false;
private final int XLARGE = 0x4;
public DialView(Context context, AttributeSet attrs) {
super(context, attrs);
mContext = context;
int screenLayout = mContext.getApplicationContext().getResources().getConfiguration().screenLayout;
mArrow = Utilities.applyFilter(context, BitmapFactory.decodeResource(context.getResources(), R.drawable.wind_arrow));
}
@Override
public void onDraw(Canvas canvas) {
float degrees = 0.0f;
degrees = (!isHourly) ? cardinalToDegrees(mWdm) : cardinalToDegrees(mWdm.hourly.get(mHourIndex));
Bitmap bit;
int originY = getHeight() / 2;
int originX = getWidth() / 2;
int r = originY > originX ? getWidth() * 8 / 27 : getHeight() * 8 / 27;
int x, y;
Matrix matrix = new Matrix();
degrees = (previousAngle * (iters / 10.0f) + degrees * (10.0f - iters) / 10.0f);
//Log.d(DEBUG_TAG, "Previous angle = " + previousAngle + " degrees" + degrees);
matrix.postRotate(degrees - 90.f);
bit = Bitmap.createBitmap(mArrow, 0, 0, mArrow.getWidth(), mArrow.getHeight(), matrix, false);
x = (int)(Math.cos(Math.PI * degrees / 180.0f) * r) + originX - (bit.getWidth() / 2);
y = (int)(Math.sin(Math.PI * degrees / 180.0f) * r) + originY - (bit.getHeight() / 2);
//Log.d(DEBUG_TAG, "x: " + x + " y: " + y);
canvas.drawBitmap(bit, x, y, null);
if (iters > 0) {
invalidate();
iters--;
}
previousAngle = degrees;
}
Here is the arrow good:
Here it is pixelated:
如何处理这一问题的想法?