当我在 Java方案中使用经营者百分比时,我不断得到负面的答复。 例:-1% -1. 虽然这在数学上是正确的,但我希望获得正常的数学解决办法,即99。 换言之,我要找到最小的正面愤怒解决办法。 Java是否找到了简单的解决办法(也许我在数学上忽略了什么)。 纽约总部 我无法找到吗?
我也想澄清,如果在APIC中有某种内容的话,这种联系会非常麻烦。
当我在 Java方案中使用经营者百分比时,我不断得到负面的答复。 例:-1% -1. 虽然这在数学上是正确的,但我希望获得正常的数学解决办法,即99。 换言之,我要找到最小的正面愤怒解决办法。 Java是否找到了简单的解决办法(也许我在数学上忽略了什么)。 纽约总部 我无法找到吗?
我也想澄清,如果在APIC中有某种内容的话,这种联系会非常麻烦。
你们能够这样做吗?
int d = 100;
int x = -1 % d;
if (x < 0)
x += d;
应为任何积极的<代码>d而努力。
你可以做以下工作:
int myMod(int x, int modulo)
{
return ((x % modulo) + modulo) % modulo
}
这样做是为了达到任何替代 d或x的数值。
int d=100;
int x=-1%d;
while (x<0)
x+=d;
i < 0 ? n - ((-i - 1) % n + 1) : i % n
例如:
class Mod {
public static int mod(int i, int n) {
return i < 0 ? n - ((-i - 1) % n + 1) : i % n;
}
public static void main(String [] args) {
System.out.println("mod(-201, 100) == " + mod(-201, 100));
System.out.println("mod(-200, 100) == " + mod(-200, 100));
System.out.println("mod(17, 100) == " + mod(17, 100));
System.out.println("mod(100, 100) == " + mod(100, 100));
}
}
而且
$ javac Mod.java && java Mod
mod(-201, 100) == 99
mod(-200, 100) == 0
mod(17, 100) == 17
mod(100, 100) == 0
无休息室。
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