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为什么C和Java的产量在2.00+(++m)中有所不同
原标题:Why output differs in C and Java in the expression m++ + (++m) [duplicate]

考虑:

int m = 2, n;

n = m++ + (++m);

C产出为:

m = 4, n = 4;

在 Java的产出中:

m = 4, n = 5;

情况如何?

最佳回答

由于C不允许一个含有这种表述的正确方案――C没有界定这种方案的行为,因此可能有所不同。 这使得汇编者在解释这些表述时具有广泛的自由度。

Java更严格地限制执行工作,界定了类似表达方式的预期行为。

(C中这种突破的一条规则是,未经中间顺序点,表达不得不止一次更改物体的价值。)

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