Question

我发现难以解释视力演播室登记窗口中的Xmm登记册的价值。窗口显示:

XMM0 = 00000000000000004018000000000000 XMM1 = 00000000000000004020000000000000 
XMM2 = 00000000000000000000000000000000 XMM3 = 00000000000000000000000000000000 
XMM4 = 00000000000000000000000000000000 XMM5 = 00000000000000000000000000000000 
XMM6 = 00000000000000000000000000000000 XMM7 = 00000000000000000000000000000000 

XMM00 = +0.00000E+000      XMM01 = +2.37500E+000      XMM02 = +0.00000E+000      
XMM03 = +0.00000E+000      XMM10 = +0.00000E+000      XMM11 = +2.50000E+000      
XMM12 = +0.00000E+000      XMM13 = +0.00000E+000

从我手头的法典来看,XMM0和XMM1的价值应当是6和8(或其他方式的圆)。登记价值如下:XMM01 = +2.37500E+000。

这样做是怎样的?

Answer 1

Yes, it looks like:

XMM0 = { 6.0, 0.0 }  // 6.0 = 0x4018000000000000 (double precision)
XMM1 = { 8.0, 0.0 }  // 8.0 = 0x4020000000000000 (double precision)

The reason you are having problems interpreting this is that your debugger is only displaying each 128 bit XMM register in hex and then below that as 4 x single precision floats, but you are evidently using double precision floats.

我不熟悉“演播室”视像会议,但最好有办法改变贵会名册的代表性,你们也许必须看看手册或网上帮助。

Note that in general using double precision with SSE is rarely of any value, particularly if you have a fairly modern x86 CPU with two FPUs.

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