Question

是否可能? 我尝试如下:

rows=db().select(db.division.ALL, db.department.ALL, db.section.ALL, 
    left=db.section.on(db.department.id==db.section.department_id) & 
    db.department.on(db.division.id==db.department.division_id))

傲慢说,不支持。

Answer 1

作为清单:

left=[db.section.on(db.department.id==db.section.department_id),
      db.department.on(db.division.id==db.department.division_id)]

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