Question

我正在使用一个网址的文字来计算特定时间之间的时间差,你可以在此看到:。

我刚刚指出,文字有点::当开始时间在午夜之前[请说22:30],结束时间是在午夜之后[请说:00:30],功能赢得了笔工作。

Can you help me fix that? This is the script used:

    function get_time_difference( $start, $end )
{
    $uts[ start ]      =    strtotime( $start );
    $uts[ end ]        =    strtotime( $end );
    if( $uts[ start ]!==-1 && $uts[ end ]!==-1 )
    {
        if( $uts[ end ] >= $uts[ start ] )
        {
            $diff    =    $uts[ end ] - $uts[ start ];
            if( $days=intval((floor($diff/86400))) )
                $diff = $diff % 86400;
            if( $hours=intval((floor($diff/3600))) )
                $diff = $diff % 3600;
            if( $minutes=intval((floor($diff/60))) )
                $diff = $diff % 60;
            $diff    =    intval( $diff );            
            return( array( days =>$days,  hours =>$hours,  minutes =>$minutes,  seconds =>$diff) );
        }
        else
        {
            trigger_error( "Ending date/time is earlier than the start date/time", E_USER_WARNING );
        }
    }
    else
    {
        trigger_error( "Invalid date/time data detected", E_USER_WARNING );
    }
    return( false );
}

Answer 1

为什么不使用 getdate( function 相反? 那么,你可以肯定,你的法典是行之有效的,不管你说什么是“不工作”。

function get_time_difference($start, $end)
{
    $uts[ start ]      =    strtotime($start);
    $uts[ end ]        =    strtotime($end);
    if ($uts[ start ] !==-1 && $uts[ end ] !==-1)
    {
        if( $uts[ end ] >= $uts[ start ] )
        {     
            return getdate($uts[ end ] - $uts[ start ]);
        }
        else
        {
            trigger_error("Ending date/time is earlier than the start date/time", E_USER_WARNING);
        }
    }
    else
    {
        trigger_error("Invalid date/time data detected", E_USER_WARNING);
    }
    return(false);
}

友情链接