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分配给方法参数的面积
原标题:Size allocated for parameters sent to a method

Is there a way to know what is size of the allocated space for the parameters sent to a function if I know its frame pointer and return address?
(preferably without using debug symbols)

最佳回答

总的来说,第2号。 从一开始,你不了解打电话的公约,因此,你不知道这些参数是如何通过的,谁应该清除这些参数。 即便你确实知道所谓的公约,我也认为,在确定你要求什么方面,还有一丝不.的证明。

问题回答

通常见到这样的职能;

myFunction(char* buffer, int bufferSize, ...) { ... }

如果不把空间作为第二小段(或结构),你不能确定分配空间。 但是,如果这是个有重大限制的地段或又一个地段,你可以检查其数量(而不是所分配的空间)。

edit: to get parameter sizes, you need to use va_list, va_start, va_arg, va_end library functions.

If all the data is allocated on the stack, then for a function foo(par1, par2, ..., par10) the size of parameters par1, ..., par9 should be ((long) &par10) - ((long) &par1).

您可在参数清单末尾添加一滴米参数,这样就可以确定所有实际参数的规模。





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