Question

NSString *str= @"surname";
NSMutableString *consonants = [[NSMutableString alloc] init];
NSMutableString *vowels = [[NSMutableString alloc] init];

for (int i=0; i < [str length]; i++){
    if ([str characterAtIndex:i] !=  a  && [str characterAtIndex:i] !=  e  && [str characterAtIndex:i] !=  i  && [str characterAtIndex:i] !=  o  && [str characterAtIndex:i] !=  u ) {
            [consonants appendFormat:@"%c",[str characterAtIndex:i]];
        }
        else{
            [vowels appendFormat:@"%c",[str characterAtIndex:i]];
        }
    }


 if([consonants length] < 3){
      [consonants appendFormat:@"%@", [vocali characterAtIndex:1]];
 }

My problem is the follow:
if there are less of 3 consonant, I must append n vowels to consonants string.

Examples:
str = "mario";
consonants = "mra"; // 2 consonants and 1 vowels

str = leo;
consonants = "leo"; // 1 consonant and 2 vowels

页: 1

Answer 1

如果你知道,所提供的投入将更大或等于3个,那么你就只能使用一种工具:

int i = 0;
while([consonant length]<3){
   [consonant appendFormat:@"%c",[vocali characterAtIndex:i]];
   i++
}

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