Question

如果所有露天浏览器窗户都与试图获得名单的窗户相同,则是否有办法获得一份名单?

Answer 1

总的来说,第2号。

除非窗户之间有“连接”(例如,一个窗口使用<条码>窗口>开放/代码>打开所有其他窗口),否则浏览器窗户因安全原因可以进行交流。

<><>Edit>:

如果你给你的窗户分配一个名字,你可以在更新母子之后重新控制。

www.un.org/Depts/DGACM/index_spanish.htm Var = 窗口.open(一些Page.html,WergeName ); 开放儿童窗口,名称为windowName。
After refreshing the parent page, windowVar = window.open( , windowName ); re-associates the variable windowVar with the window of name windowName.
现在,windowVar.place.href=logout.html>;请您登录用户。

<><>Edit>:

Assuming you use PHP, you could do something like this:

Create logged.php with a function logged_in that verifies if the session ID is still valid.

<?php
    if (isset($_GET[ sid ]))
            if (logged_in($_GET[ sid ]))
            echo "in";
    else
            echo "out";
?>

在您的网页中列入<编码>check()。

function check()
{
    var url = "http://redtwitz.com/test/logged.php?sid=" + sessionId;
    var request;
    try
    {
        request = new XMLHttpRequest();
    }
    catch(error1)
    {
        try
        {
            request = new ActiveXObject("Msxml2.XMLHTTP");
        }
        catch(error2)
        {
            request = new ActiveXObject("Microsoft.XMLHTTP");
        }
    }
    request.open("GET", url, false);
    request.setRequestHeader("User-Agent",navigator.userAgent);
    request.send(null);
    if(request.status==200)
        if(request.responseText == "out")
            window.location.href = "logout.html";
}

电话检查每5秒进行。

<body onload="setInterval(check, 5000);">

Answer 2

Alternatively, you can implement Chrome extension and do your task by using extension api: http://code.google.com/chrome/extensions/tabs.html But it will work in Chrome browser only.

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