我继承了一个相当庞大的LQ服务器数据库。 鉴于其中的数据,它似乎占用了比我预期更多的空间。
Is there an easy way to determine how much space on disk each table is consuming?
我继承了一个相当庞大的LQ服务器数据库。 鉴于其中的数据,它似乎占用了比我预期更多的空间。
Is there an easy way to determine how much space on disk each table is consuming?
SELECT
t.name AS TableName,
s.name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.object_id = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.name NOT LIKE dt%
AND t.is_ms_shipped = 0
AND i.object_id > 255
GROUP BY
t.name, s.name, p.rows
ORDER BY
TotalSpaceMB DESC, t.name
如果您使用SQL服务器管理(SSMS),而不是进行查询(,在我的案件中,重复浏览),你可以操作
注:数据库的兼容性水平必须定为90或以上,以便正确开展工作。 见。
注: 2. 本报告在与S.K.和T.K.数据库合作时提供。
间谍——用户可在磁盘空间上获取有关表格、索引观点或整个数据库所使用的信息。
例如:
USE MyDatabase; GO
EXEC sp_spaceused N User.ContactInfo ; GO
本报告载有联系信息表的磁盘使用信息。
a. 所有表格一律使用:
USE MyDatabase; GO
sp_msforeachtable EXEC sp_spaceused [?] GO
也可以从服务器KQ右翼标准报告功能中获取磁盘使用。 为了阅读本报告,从目标探索者服务器物体上航行,进入数据库物体,然后对数据库进行正确扫描。 从表中的菜单中,选择报告,然后是标准报告,然后是“分部分使用:[数据基Name]”。
exec sp_spaceused N dbo.MyTable
(摘自保罗的评论)
exec sp_MSForEachTable exec sp_spaceused [?]
在进行了一些搜索之后,我找不到容易获得所有表格信息的途径。 有一个称为“间谍”的手工存储程序,将归还数据库使用的所有空间。 如果提供了一张表格名称,则该表所用的空间即告回。 然而,通过储存程序返还的结果是无法区分的,因为各栏是特性值。
以下文字将产生信息Im。
create table #TableSize (
Name varchar(255),
[rows] int,
reserved varchar(255),
data varchar(255),
index_size varchar(255),
unused varchar(255))
create table #ConvertedSizes (
Name varchar(255),
[rows] int,
reservedKb int,
dataKb int,
reservedIndexSize int,
reservedUnused int)
EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused ? "
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows],
SUBSTRING(reserved, 0, LEN(reserved)-2),
SUBSTRING(data, 0, LEN(data)-2),
SUBSTRING(index_size, 0, LEN(index_size)-2),
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize
select * from #ConvertedSizes
order by reservedKb desc
drop table #TableSize
drop table #ConvertedSizes
以上查询对于寻找表格所使用的空间数量(包括索引)来说是好的,但如果您想比较表格中索引所使用的空间数量,则使用这一查询:
SELECT
OBJECT_NAME(i.OBJECT_ID) AS TableName,
i.name AS IndexName,
i.index_id AS IndexID,
8 * SUM(a.used_pages) AS Indexsize(KB)
FROM
sys.indexes AS i
JOIN sys.partitions AS p ON p.OBJECT_ID = i.OBJECT_ID AND p.index_id = i.index_id
JOIN sys.allocation_units AS a ON a.container_id = p.partition_id
WHERE
i.is_primary_key = 0 -- fix for size discrepancy
GROUP BY
i.OBJECT_ID,
i.index_id,
i.name
ORDER BY
OBJECT_NAME(i.OBJECT_ID),
i.index_id
Marc_s answer gives incorrect results when working with multiple partitions and/or filtered indexes. It also doesn t distinguish between the size of the data and indexes, which is often very relevant. Several suggested fixes don t address the core problem or are simply wrong as well.
The following query addresses all of those issues.
SELECT
[object_id] = t.[object_id]
,[schema_name] = s.[name]
,[table_name] = t.[name]
,[index_name] = CASE WHEN i.[type] in (0,1,5) THEN null ELSE i.[name] END -- 0=Heap; 1=Clustered; 5=Clustered Columnstore
,[object_type] = CASE WHEN i.[type] in (0,1,5) THEN TABLE ELSE INDEX END
,[index_type] = i.[type_desc]
,[partition_count] = p.partition_count
,[row_count] = p.[rows]
,[data_compression] = CASE WHEN p.data_compression_cnt > 1 THEN Mixed
ELSE ( SELECT DISTINCT p.data_compression_desc
FROM sys.partitions p
WHERE i.[object_id] = p.[object_id] AND i.index_id = p.index_id
)
END
,[total_space_MB] = cast(round(( au.total_pages * (8/1024.00)), 2) AS DECIMAL(36,2))
,[used_space_MB] = cast(round(( au.used_pages * (8/1024.00)), 2) AS DECIMAL(36,2))
,[unused_space_MB] = cast(round(((au.total_pages - au.used_pages) * (8/1024.00)), 2) AS DECIMAL(36,2))
FROM sys.schemas s
JOIN sys.tables t ON s.schema_id = t.schema_id
JOIN sys.indexes i ON t.object_id = i.object_id
JOIN (
SELECT [object_id], index_id, partition_count=count(*), [rows]=sum([rows]), data_compression_cnt=count(distinct [data_compression])
FROM sys.partitions
GROUP BY [object_id], [index_id]
) p ON i.[object_id] = p.[object_id] AND i.[index_id] = p.[index_id]
JOIN (
SELECT p.[object_id], p.[index_id], total_pages = sum(a.total_pages), used_pages = sum(a.used_pages), data_pages=sum(a.data_pages)
FROM sys.partitions p
JOIN sys.allocation_units a ON p.[partition_id] = a.[container_id]
GROUP BY p.[object_id], p.[index_id]
) au ON i.[object_id] = au.[object_id] AND i.[index_id] = au.[index_id]
WHERE t.is_ms_shipped = 0 -- Not a system table
Extension to @xav answer that handled table partitions to get size in MB and GB.
Tested on SQL Server 2008/2012 (Commented a line where is_memory_optimized = 1
)
SELECT
a2.name AS TableName,
a1.rows as [RowCount],
--(a1.reserved + ISNULL(a4.reserved,0)) * 8 AS ReservedSize_KB,
--a1.data * 8 AS DataSize_KB,
--(CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS IndexSize_KB,
--(CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS UnusedSize_KB,
CAST(ROUND(((a1.reserved + ISNULL(a4.reserved,0)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS ReservedSize_MB,
CAST(ROUND(a1.data * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS DataSize_MB,
CAST(ROUND((CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS IndexSize_MB,
CAST(ROUND((CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSize_MB,
-- | | Separator_MB_GB,
CAST(ROUND(((a1.reserved + ISNULL(a4.reserved,0)) * 8) / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS ReservedSize_GB,
CAST(ROUND(a1.data * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS DataSize_GB,
CAST(ROUND((CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS IndexSize_GB,
CAST(ROUND((CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSize_GB
FROM
(SELECT
ps.object_id,
SUM (CASE WHEN (ps.index_id < 2) THEN row_count ELSE 0 END) AS [rows],
SUM (ps.reserved_page_count) AS reserved,
SUM (CASE
WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
END
) AS data,
SUM (ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
--===Remove the following comment for SQL Server 2014+
--WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN
(SELECT
it.parent_id,
SUM(ps.reserved_page_count) AS reserved,
SUM(ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
WHERE it.internal_type IN (202,204)
GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2 ON ( a1.object_id = a2.object_id )
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N S and a2.type <> N IT
--AND a2.name = MyTable --Filter for specific table
--ORDER BY a3.name, a2.name
ORDER BY ReservedSize_MB DESC
如果你需要计算表层财产上的相同数字——SSMS的储存页数,那么你需要将其与SSMS的相同方法加以计算(用于舱面服务器的工程,2005年及以上......,并且与LOB油田的表格正确操作——因为仅仅计算“旧页数”不足以显示准确的指数规模:
;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END) as pages
FROM sys.dm_db_partition_stats AS s
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
cte.TableName,
cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB,
cast(((CASE WHEN cte.used_pages_count > cte.pages
THEN cte.used_pages_count - cte.pages
ELSE 0
END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc
缩略语:
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE dt%
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
--p.rows DESC --Uncomment to order by amount rows instead of size in KB.
SUM(a.total_pages) DESC
由于重复记录,我们采用表格分门别类,并对上文提出的问题有一些麻烦。
对于需要的人,在提出“按表格分列的使用情况”报告时,你可以发现在“服务器2014年”的盘问下。 我也认为它与以前的服务器版本合作。
它与一家药店一样。
SELECT
a2.name AS [tablename],
a1.rows as row_count,
(a1.reserved + ISNULL(a4.reserved,0))* 8 AS reserved,
a1.data * 8 AS data,
(CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS index_size,
(CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS unused
FROM
(SELECT
ps.object_id,
SUM (
CASE
WHEN (ps.index_id < 2) THEN row_count
ELSE 0
END
) AS [rows],
SUM (ps.reserved_page_count) AS reserved,
SUM (
CASE
WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
END
) AS data,
SUM (ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN
(SELECT
it.parent_id,
SUM(ps.reserved_page_count) AS reserved,
SUM(ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
WHERE it.internal_type IN (202,204)
GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2 ON ( a1.object_id = a2.object_id )
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N S and a2.type <> N IT
ORDER BY a3.name, a2.name
-- Show the size of all the tables in a database sort by data size descending
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = exec sp_spaceused ?
INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1
SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA, KB , )) DESC
下面是迅速实现所有表格规模的一条途径,其步骤如下:
<>T-SQL 指挥以列出所有数据库表:
select exec sp_spaceused + TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_TYPE = BASE TABLE
现在复制数据库表格清单,并将其复制成新的查询分析器
exec sp_spaceused table1
exec sp_spaceused table2
exec sp_spaceused table3
exec sp_spaceused table4
exec sp_spaceused table5
<query analyzer, 摘自最高工具条选择Results to file (Ctrl +>。
现在最后点击了上面标注的Execute,但顿红。
数据库所有表格现已储存在你的电脑档案中。
我谨感谢格雷格·洛先生:
SELECT o.name AS ObjectName,
SUM(reserved_page_count) * 8.0 / 1024 AS SizeinMB
FROM sys.dm_db_partition_stats AS ps
INNER JOIN sys.sysobjects AS o
ON ps.object_id = o.id
GROUP BY o.name
ORDER BY SizeinMB DESC;
为了在一个数据库中实现所有表层规模,你可以使用这一查询:
Exec sys.sp_MSforeachtable sp_spaceused "?"
并且,在从温室桌选择之后,你可以将其改为所有结果。
Insert into #TempTable Exec sys.sp_MSforeachtable sp_spaceused "?"
Select * from #TempTable
这将给你每个桌上的大小和记录。
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
-- Get a list of tables and their sizes on disk
ALTER PROCEDURE [dbo].[sp_Table_Sizes]
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
DECLARE @table_name VARCHAR(500)
DECLARE @schema_name VARCHAR(500)
DECLARE @tab1 TABLE(
tablename VARCHAR (500) collate database_default
,schemaname VARCHAR(500) collate database_default
)
CREATE TABLE #temp_Table (
tablename sysname
,row_count INT
,reserved VARCHAR(50) collate database_default
,data VARCHAR(50) collate database_default
,index_size VARCHAR(50) collate database_default
,unused VARCHAR(50) collate database_default
)
INSERT INTO @tab1
SELECT Table_Name, Table_Schema
FROM information_schema.tables
WHERE TABLE_TYPE = BASE TABLE
DECLARE c1 CURSOR FOR
SELECT Table_Schema + . + Table_Name
FROM information_schema.tables t1
WHERE TABLE_TYPE = BASE TABLE
OPEN c1
FETCH NEXT FROM c1 INTO @table_name
WHILE @@FETCH_STATUS = 0
BEGIN
SET @table_name = REPLACE(@table_name, [ , );
SET @table_name = REPLACE(@table_name, ] , );
-- make sure the object exists before calling sp_spacedused
IF EXISTS(SELECT id FROM sysobjects WHERE id = OBJECT_ID(@table_name))
BEGIN
INSERT INTO #temp_Table EXEC sp_spaceused @table_name, false;
END
FETCH NEXT FROM c1 INTO @table_name
END
CLOSE c1
DEALLOCATE c1
SELECT t1.*
,t2.schemaname
FROM #temp_Table t1
INNER JOIN @tab1 t2 ON (t1.tablename = t2.tablename )
ORDER BY schemaname,t1.tablename;
DROP TABLE #temp_Table
END
https://msdn.microsoft.com/en-us/library/ms162806.aspx” rel=“nofollow” OSQL:
OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable sp_spaceused [?] " > result.txt
也许,表格中还有一部分文件,必须显示档案命令。
SELECT
T1.Name AS TableName,
T5.Name AS SchemaName,
T3.partition_number AS PartionNumber,
T3.Rows AS RowsCount,
SUM(T4.total_pages) * 8 AS TotalSpaceKB,
SUM(T4.used_pages) * 8 AS UsedSpaceKB,
(SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.objects T1 INNER JOIN
sys.indexes T2 ON T1.object_id = T2.object_id INNER JOIN
sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id INNER JOIN
sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
T1.type= U
GROUP BY
T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
T1.Name,T3.partition_number;
我在武克的答复中增加了几栏:
with fs
as
(
select i.object_id,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKb
from sys.indexes i INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.OBJECT_ID > 255
GROUP BY
i.object_id,
p.rows
)
SELECT
t.NAME AS TableName,
fs.RowCounts,
fs.TotalSpaceKb,
t.create_date,
t.modify_date,
( select COUNT(1)
from sys.columns c
where c.object_id = t.object_id ) TotalColumns
FROM
sys.tables t INNER JOIN
fs ON t.OBJECT_ID = fs.object_id
WHERE
t.NAME NOT LIKE dt%
AND t.is_ms_shipped = 0
ORDER BY
t.Name
我的这个职位仅与LQ服务器2000有关,并在我的环境下工作。
本条准则的查阅。 单例的所有可能数据库,而不仅仅是一个数据库。
我使用两个图表帮助收集适当的数据,然后把结果放在一个活桌上。
回归数据是:数据库Name、数据库可达纳梅、Ros(表格)、数据(表似乎在KB中的表格)、输入数据(我发现这有利于了解我最后掌握的文字)。
该法典的缺点是,数据领域没有作为内线储存(KB存放在外地),这对分类是有益的(但并非完全必要的)。
希望这部法律帮助人们走出来,节省了一段时间!
CREATE PROCEDURE [dbo].[usp_getAllDBTableSizes]
AS
BEGIN
SET NOCOUNT OFF
CREATE TABLE #DatabaseTables([dbname] sysname,TableName sysname)
CREATE TABLE #AllDatabaseTableSizes(Name sysname,[rows] VARCHAR(18), reserved VARCHAR(18), data VARCHAR(18), index_size VARCHAR(18), unused VARCHAR(18))
DECLARE @SQL nvarchar(4000)
SET @SQL= select ? AS [Database], Table_Name from [?].information_schema.tables WHERE TABLE_TYPE = BASE TABLE
INSERT INTO #DatabaseTables(DbName, TableName)
EXECUTE sp_msforeachdb @Command1=@SQL
DECLARE AllDatabaseTables CURSOR LOCAL READ_ONLY FOR
SELECT TableName FROM #DatabaseTables
DECLARE AllDatabaseNames CURSOR LOCAL READ_ONLY FOR
SELECT DBName FROM #DatabaseTables
DECLARE @DBName sysname
OPEN AllDatabaseNames
DECLARE @TName sysname
OPEN AllDatabaseTables
WHILE 1=1 BEGIN
FETCH NEXT FROM AllDatabaseNames INTO @DBName
FETCH NEXT FROM AllDatabaseTables INTO @TName
IF @@FETCH_STATUS<>0 BREAK
INSERT INTO #AllDatabaseTableSizes
EXEC ( EXEC + @DBName + .dbo.sp_spaceused + @TName)
END
--http://msdn.microsoft.com/en-us/library/aa175920(v=sql.80).aspx
INSERT INTO rsp_DatabaseTableSizes (DatabaseName, name, [rows], data)
SELECT [dbname], name, [rows], data FROM #DatabaseTables
INNER JOIN #AllDatabaseTableSizes
ON #DatabaseTables.TableName = #AllDatabaseTableSizes.Name
GROUP BY [dbname] , name, [rows], data
ORDER BY [dbname]
--To be honest, I have no idea what exact duplicates we are dropping
-- but in my case a near enough approach has been good enough.
DELETE FROM [rsp_DatabaseTableSizes]
WHERE name IN
(
SELECT name
FROM [rsp_DatabaseTableSizes]
GROUP BY name
HAVING COUNT(*) > 1
)
DROP TABLE #DatabaseTables
DROP TABLE #AllDatabaseTableSizes
CLOSE AllDatabaseTables
DEALLOCATE AllDatabaseTables
CLOSE AllDatabaseNames
DEALLOCATE AllDatabaseNames
END
--EXEC [dbo].[usp_getAllDBTableSizes]
In case you need to know, the rsp_DatabaseTableSizes table was created through:
CREATE TABLE [dbo].[rsp_DatabaseSizes](
[DatabaseName] [varchar](1000) NULL,
[dbSize] [decimal](15, 2) NULL,
[DateUpdated] [smalldatetime] NULL
) ON [PRIMARY]
GO
Riffing on Mark回答 above, supplemented the @updateusage= real to force the recent small stats ( https://msdn.microsoft.com/en-us/library/ms188776.aspx :
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = exec sp_spaceused @objname = ? , @updateusage = true
INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1
SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA, KB , )) DESC
这里的样本是,通过规模缩小而订购的桌位大于1GB。
USE YourDB
GO
DECLARE @Mult float = 8
SET @Mult = @Mult / POWER(2, 20) -- Use POWER(2, 10) for MBs
; WITH CTE AS
(
SELECT
i.object_id,
Rows = MAX(p.rows),
TotalSpaceGB = ROUND(SUM(a.total_pages) * @Mult, 0),
UsedSpaceGB = ROUND(SUM(a.used_pages) * @Mult, 0)
FROM
sys.indexes i
JOIN
sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.object_id > 255
GROUP BY
i.object_id
HAVING
SUM(a.total_pages) * @Mult > 1
)
SELECT
SchemaName = s.name,
TableName = t.name,
c.TotalSpaceGB,
c.UsedSpaceGB,
UnusedSpaceGB = c.TotalSpaceGB - c.UsedSpaceGB,
[RowCount] = c.Rows
FROM
CTE c
JOIN
sys.tables t ON t.object_id = c.object_id
JOIN
sys.schemas s ON t.schema_id = s.schema_id
ORDER BY
c.TotalSpaceGB DESC
https://stackoverflow.com/a/7892349/1501497">。
SELECT *
FROM
(
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
(SUM(a.used_pages) * 8) AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE dt%
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
) AS Result
WHERE
RowCounts > 1000
AND ColumnCount > 10
ORDER BY
UsedSpaceKB DESC
I found this query to be easy to use & quick.
select schema_name(tab.schema_id) + . + tab.name as [table],
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind
on tab.object_id = ind.object_id
inner join sys.partitions (nolock) part
on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + . + tab.name
order by sum(spc.used_pages) desc
红十字与红新月联会只关注数据库中空闲的空闲空间,而不是你可以考虑的个别表格:
If the database experiences large amount of data insertion and then deletions, maybe like in an ETL situation, this will cause too much unused space in the database as the file groups auto-grows but never auto-shrinks back.
你们可以通过使用贵国数据库<>Properties网页来了解情况。 您可以缩小(直线点击数据库;任务和任务;Shrink),并申请一些空间。 但是,如果仍然有根本原因,数据库就会回落(并消耗额外的时间,试图回落,而事情在增长得足够之前已经放慢——在这种情况下就没有这样做了)。
CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed
(
TableName sysname
,NumRows BIGINT
,ReservedSpace VARCHAR(50)
,DataSpace VARCHAR(50)
,IndexSize VARCHAR(50)
,UnusedSpace VARCHAR(50)
)
insert into #tmp_table_info
select s.name+ . +t.name
from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = U ;
declare @min int =1,@max int = 0
select @max = count(*)
from #tmp_table_info
while(@min<=@max)
begin
declare @tablename varchar(200)
select @tablename=tblname
from #tmp_table_info
where id =@min
DECLARE @str VARCHAR(500)
SET @str = sp_spaceused +@tablename+
INSERT INTO #SpaceUsed
EXEC (@str)
set @min =@min + 1
end;
select @@SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace, KB , )) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace, KB , )) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize, KB , )) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace, KB , )) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed
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