Question

I have this data in my table:

onum    amt         odate                       cnum    snum

3001    18,69       1990-03-10 00:00:00.000     2008    1007
3002    1900,10     1990-03-10 00:00:00.000     2007    1004
3003    767,19      1990-03-10 00:00:00.000     2001    1001
3005    5160,45     1990-03-10 00:00:00.000     2003    1002
3006    1098,16     1990-03-10 00:00:00.000     2008    1007
3007    75,75       1990-03-10 00:00:00.000     2004    1002
3008    4723,00     1990-05-10 00:00:00.000     2006    1001
3009    1713,23     1990-04-10 00:00:00.000     2002    1003
3010    1309,95     1990-06-10 00:00:00.000     2004    1002
3011    9891,88     1990-06-10 00:00:00.000     2006    1001

I need get this result:

amt         odate                       snum

5160,45     1990-03-10 00:00:00.000     1002
4723,00     1990-05-10 00:00:00.000     1001
9891,88     1990-06-10 00:00:00.000     1001

that is I select the max amt on the each day odate, but with displaying of seller snum

if I write this:

 SELECT MAX(amt), odate, snum 
 FROM [Understanding].[dbo].[Orders] 
 GROUP BY odate, snum

the output is wrong because it displays the groups by days and sellers.

Answer 1

;with C as
(
  select amt,
         odate,
         snum,
         row_number() over(partition by odate order by amt desc) as rn
  from Orders
)
select amt,
       odate,
       snum
from C
where rn = 1

Answer 2

select a.*,b.snum
from
(
select MAX(amt) as amt
      ,odate 
from Orders
group by odate
)A INNER JOIN Orders B
ON A.amt = b.amt
order by a.odate

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