Question

Instead of zip-mapping two lists to get:

(zipmap ["a","b","c"] ["c","d","e"]) = {"c" "e", "b" "d", "a" "c"}

我想将第一个名单的第一个要素与第二个名单的第一个要素混在一起,以便:

("ce","bd","ac")

or in the reverse order.

Answer 1

您可使用<条码>。它可以收集多种藏书,从每卷收集到下一个内容,并作为第一个论点(在收集材料中一分即行时)将其转换成功能。因此,你可以凭空和收集。

表达

(map str ["a" "b" "c"] ["c" "d" "e"])

将首先使用“a”和“c”,然后使用“b”和“d”,然后用“c”和“e”。结果是

("ac" "bd" "ce")

Since str can takes a variable number of arguments it can be used with any number of collections. Passing in four collections, like

(map str ["a" "b" "c"] ["d" "e" "f"] ["g" "h" "i"] ["j" "k" "l"])

评价

("adgj" "behk" "cfil")