Question

我有一套干::

<div class="wrapper">
 <div class="uct_attr" data-tags="one two three four">stuff</div>
 <div class="uct_attr" data-tags="three four">stuff</div>
 <div class="uct_attr" data-tags="one three five">stuff</div>
 <div class="uct_attr" data-tags="one two six">stuff</div>
 <div class="uct_attr" data-tags="four five six">stuff</div>
</div?

我如何做,并就与我问询相匹配的问题采取行动? 牢记我的愿望是将数据标的词句同起来。

包括:

// if match  one 
$( .wrapper .uct_attr[data-tags="one"] ).doMatch();
// the rest that didn t match  one 
$( .wrapper .uct_attr[data-tags!="one"] ).doNotMatch();

我认为,这种归属有多层次的标签。

Any help on this would be great.

C. 结论

Answer 1

Simple enough: Use the member-of-a-whitespace-delimited-list selector.

var $els = $(".wrapper .uct_attr");
$els.filter("[data-tags~= one ]").doMatch();
$els.not("[data-tags~= one ]").doNotMatch();

Answer 2

not selector

$( .wrapper ).find( div ).not( .uct_attr[data-tags="one"] ).doNotMatch();

Answer 3

为在名词中添加一个词,使用此处定义的“~”操作器:。

// if match  one 
$( .wrapper .uct_attr[datatags~="one"] ).doMatch();
// the rest that didn t match  one 
$( .wrapper .uct_attr ).not( [datatags~="one"] ).doNotMatch();

友情链接