Question

I m 通过一个阵列,在每一处 lo期间,Im通过亚x指一种ur。我也希望更新一个内部的超文本,以便显示它能够随时向用户通报正在处理该排他性的问题。然而,在文字完稿时,只显示最新情况。

我怎么能够在我的休息时间表明这一通知?

I m also using the query ajax setting async: false . I don t want to hammer my server with processing all of the ajax requests at once, as they are encoding video files which is CPU intensive. I don t really want to lock the browser up waiting for synchronous requests to complete either.

是否有更好的办法这样做?

我的最终目标是依次执行我的组合。每一套录像带的网址,同时向用户展示当前状况指标,同时不把浏览器锁在这一过程之中。感谢你们的帮助!

这里的《法典》:

www.un.org/Depts/DGACM/index_spanish.htm

// process the loop of videos to be combined
    var status = document.getElementById( currentStatus );
    for (i=0; i< count; i++) {

        // change the display

        var fields = videos[i].split(":", 2);

        current = i +1;

        currentStatus.innerHTML = "<b>Multi-part Videos:</b>&nbsp;&nbsp;&nbsp; <h3 class= status >Currently Updating Bout #" + fields[1] + " (" + current + " of " + count + " videos)</h3>";



        // run the combine 
        var dataString =  videoId= + fields[0]; 



        $.ajax({  
            type: "POST",  
            url: "combine.php",  
            data: dataString,  
            success: function(txt) {


                //deselect the checkbox

                document.combine.video[selected[i]].checked = false;
            },
            async: false 
        });

Answer 1

如果你想要在把一对一对一字确定为事实时加以更新,则下一次请求可以成功执行。更新地位法也应属于这一职能。

function ajaxRequest(i){

        // other processing
        .............

        $.ajax({  
            type: "POST",  
            url: "combine.php",  
            data: dataString,  
            success: function(txt) {

                //deselect the checkbox
                document.combine.video[selected[i]].checked = false;

                // update status
                currentStatus.innerHTML = .....
                // make next request
                if(i<lastOne){
                     ajaxRequest(i+1);
                }
            },
            async: true
        }); 
}

Answer 2

async: false will hang the entire browser until the ajax request completes. That is why you don t see the page update on each loop iteration.

同步的亚克斯请求通常会为可怕的未爆炸物质(如:you)提出,如冻结不重复的网页? 自您使用j Query以来,。递延目标APIC/a”使这一点变得容易。

Answer 3

正如其他人已经提到的那样,你的问题之所以出现,是因为贾瓦文只读一读了——虽然唯一的一份联合材料正等待你提出回去的要求,但不允许它更新联合调查。

You can get around this by changing the request to async, and using the callback to trigger the request for the next object:

// trigger the loop of videos to be combined
var status = document.getElementById( currentStatus );
processVideo( 0 );

function processVideo( index ) {
    var fields = videos[index].split(":", 2);

    currentStatus.innerHTML = "<b>Multi-part Videos:</b>&nbsp;&nbsp;&nbsp; <h3 class= status >Currently Updating Bout #" + fields[1] + " (" + current + " of " + count + " videos)</h3>";

    // run the combine 
    var dataString =  videoId= + fields[0]; 

    $.ajax({  
        type: "POST",  
        url: "combine.php",  
        data: dataString,  
        success: function() {
           processResponse( index);
        },
        async: true
    });
}

function processResponse( index ) {
   // this method is called each time the ajax request finishes
   if (index++ < count) {
      //deselect the checkbox
      document.combine.video[selected[index]].checked = false;

      processVideo( index );
   }
}

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