Question

我尝试研究<代码>(int),但只能找到PHP手册中的功能int()。

难道有人能向我解释上述法典是什么,以及它是如何运作的?

Answer 1

它将(至少是尝试)变数的任何价值都转换为ger。如果有任何信件等,它就将改为0。

<?php

$var =  1a ;

echo $var;               // 1a
echo (int) $var;     //1

$var2 =  a2 ;
echo $var2;           //a2
echo (int) $var2;     // 0

?>

Answer 2

<代码>(int)将某一数值转换为单位。

<?php
$test = "1";
echo gettype((int)$test);
?>

$ php test.php
integer

Answer 3

简单的例子将使你理解:

var_dump((int)8);
var_dump((int)"8");
var_dump((int)"6a6");

var_dump((int)"a6");

var_dump((int)8.9);
var_dump((int)"8.9");
var_dump((int)"6.4a6");

结果:

int(8)
int(8)
int(6)

int(0)

int(8)
int(8)
int(6)

Answer 4

在PHP中,(int)将具有以下价值:int。

例:

php > var_dump((int) "5");
int(5)

I believe the syntax was borrowed from C.

Answer 5

你们正在研究的是:打字/体格>类型,以获得更多的信息,见 juggling 。

以上编码(或转换)_GET[ page]至 integer。

Answer 6

这类合成物<代码>(int)称为打字。从根本上说,它采用了随之产生的变量,并试图将其变成一个<条码>。

Answer 7

(int)与(t)相同。

see http://php.net/manual/en/language.types.integer.php

Answer 8

it casts the variable following it to integer. more info from documentation: http://php.net/manual/en/language.types.type-juggling.php

Type casting in PHP works much as it does in C: the name of the desired type is written in parentheses before the variable which is to be cast.

允许的投票是:

(int), (integer) - cast to integer

(bool), (boolean) - cast to boolean

(float), (double), (real) - cast to float

(string) - cast to string

(array) - cast to array (object) - cast to object

(unset) - cast to NULL

友情链接