守则权利。 鉴于
Bitmap bitmap = BitmapFactory.decodeResource(getResources(), resId);
Drawable drawable = getResources().getDrawable(resId);
我
bitmap.getWidth() == drawable.getIntrinsicWidth() == 9
实际形象为<代码>6x6。 密度为 位置图的密度似乎没有变化。 我应该怎样问一下在真实情况下的六氯苯的形象? 我将不把所有东西分开(甚至不可能)。 增 编1.5>/code>至DENSITY_DEFAULT = 160。 这不是这样一个问题本身,而是“条形图”:植被(x, y);
首先对这里发生的情况发表一些评论。 你获得的比特图实际上已经翻版;其子数据为9x9图像。 方法bitmap.getWidth(>不受下列要求的影响:bitmap.setDensity(>。
To load the Bitmap while preventing the Android framework from resampling it for you, create a BitmapFactory.Options instance and set inScaled to false, then pass this to decodeResource():
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap bitmap = BitmapFactory.decodeResource(getResources(), resId, options);
// Now bitmap.getWidth() == 6
请注意,该表是万国邮联(除非你明确围绕该版本开展工作)中使用的“再版”,因此,如果你想要填写<条码>地图>。
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