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铁路成员行道应当容易?
原标题:Rails member routing, should be easy?

路线:

resources :projects do
  member do
    resources :stakeholders
  end
end

由此产生的路线是:

    projects_stakeholders GET    /projects/projects/:id/stakeholders(.:format)                                                  {:action=>"index", :controller=>"projects/stakeholders"}
                          POST   /projects/projects/:id/stakeholders(.:format)                                                  {:action=>"create", :controller=>"projects/stakeholders"}
    new_projects_stakeholder GET    /projects/projects/:id/stakeholders/new(.:format)                                              {:action=>"new", :controller=>"projects/stakeholders"}
    edit_projects_stakeholder GET    /projects/projects/:id/stakeholders/:id/edit(.:format)                                         {:action=>"edit", :controller=>"projects/stakeholders"}
projects_stakeholder GET    /projects/projects/:id/stakeholders/:id(.:format)                                              {:action=>"show", :controller=>"projects/stakeholders"}

由于这些路线有两倍:直径,如果我有“URL”项目,则会影响到利益攸关方/11。

在我的记录档案中,我看到:

Parameters: {"id"=>"11"}

那么,我如何能够从我的控制者内部获得我的项目。

Thanks!!!

最佳回答

您不需要<代码>。 这也是事实,你应当开始在你的寄生虫中看到<代码>项目_id:

resources :projects do
  resources :stakeholders
end
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