Question

http://example.com“rel=“nofollow”http://example.com。 (www.un.org)。我的网站上有这一文字:

                        var _gaq = _gaq || [];
                          _gaq.push([ _setAccount ,  UA-xxxxx-2 ]);
                          _gaq.push([ _trackPageview ]);

                          (function() {
                                var ga = document.createElement( script ); ga.type =  text/javascript ; ga.async = true;
                                ga.src = ( https:  == document.location.protocol ?  https://ssl  :  http://www ) +  .google-analytics.com/ga.js ;
                                var s = document.getElementsByTagName( script )[0]; s.parentNode.insertBefore(ga, s);
                          })();

页: 1

还有一个问题,即想从静态的.子中自由 go光分析。我尝试了_gaq.push([_setDomainName,例如,com]);。但是,仍然看着来自静态火力的图像。

Answer 1

如果是你的话,你就应当使用以下守则:

var _gaq = _gaq || [];
_gaq.push([ _setAccount ,  UA-xxxxx-2 ]);
_gaq.push([ _setDomainName ,  .example.com ]);
_gaq.push([ _trackPageview ]);
(function() {
var ga = document.createElement( script ); ga.type =  text/javascript ; ga.async = true;
ga.src = ( https:  == document.location.protocol ?  https://ssl  :  http://www ) +  .google-analytics.com/ga.js ;
var s = document.getElementsByTagName( script )[0]; s.parentNode.insertBefore(ga, s);
})();

但指出,这也将导致把 co子送至静态子宫。孤立静态领域的最佳办法是使其成为一个不同的领域,而不是一个不同的子域。如果你把GA的厨师储存在全部领域,而不是顶层,你就会清除静态领域,但正确建立GA将更加困难。

Answer 2

The truth of the matter is, your GA account will "track pageviews" on any page that has your tracker (with your GA account#) in it (unless you have special filters set up). Now, it won t share referrer information across domains/subdomains unless it s set up to do so, but technically someone could place your tracker code on their site to inflate your site stats.

同时,你能够看到该法典的内容(URLs页)。我不知道为什么有人想这样做,但假设是可能的。

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