我用一只多角的浮板绘制了 go图。
这里是一个我感兴趣的问题:鉴于一个相对的支点,确定这一点所依赖的所有多角的最佳途径是什么。
显而易见的是,要为每个多功能体操作“多角”算法,但我很想知道,如果你有数千个多角,是否有有效的算法来回答这些询问。
改进“每个多功能”算法的唯一办法是建立一套元数据,使你能够绕过某些多动。 例如,如果对你们的数千个多功能企业来说,你有一份清单或一套清单,列出相互重叠的所有多功能,那么你将能够迅速消除许多波动点比较。 页: 1 仅对含有一点点的“第一多角”作比较,仅比较那些把最初的“多角”混为一谈/多功能,因为任何包含这一点的“多角”也必然会重复包含它的一些其他多功能。 最严重的情况是N类比较,例如,对每项执行工作的比较。
你们还可以创造多角的自然/物理区域,例如,在某些地区的多角大楼。 在硬性例子中,你能够/应该能够消除3/4多功能,以供比较。 这一切都取决于如何安排你的多功能。
But in any case, I think an improvement to the for-each algorithm lies in the creation/organization of some logical groups among your polygon collection.
I dont知道底下什么,但将的空间过滤器应用到含有多角特征的中间层,供我使用。 例是:。 WGLayer:SetSpatialFilter (OGRGeometry * poFilter) http://www.gdal.org/ogr/classOGRLayer.html#0b4ab45cf97cbc470f0d60474d3e4169 。 我想象许多地理信息系统环境具有类似特点。
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